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MYP 3 · Science

Cell Biology

60 questions across 3 sub-topics

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Cell Structure: Plant vs Animal Cells Using Microscopes Specialised Cells

Cell Structure: Plant vs Animal Cells 20 questions

QUESTION 1 4 marks Criterion A
Easy
A B C D

The diagram shows a generalised animal cell, with four structures labelled A-D.

a. Identify the structure labelled A.
[1]
b. Identify the structure labelled B.
[1]
c. Identify the structure labelled C.
[1]
d. Identify the structure labelled D.
[1]
Show complete worked solution
(a)
A is the cell (surface) membrane — the thin boundary that surrounds the cell.
(b)
B is the nucleus.
(c)
C is a mitochondrion.
(d)
D is the cytoplasm, in which small dots representing ribosomes can be seen.
QUESTION 2 8 marks Criterion A
Medium
A B C D E

The diagram shows a generalised plant cell, with five structures labelled A-E.

a. Identify structure A and state one function of this structure.
[2]
b. Identify structure B and state one function of this structure.
[2]
c. Identify structure D and state one function of this structure.
[2]
d. Identify structure E and state one function of this structure.
[2]
Show complete worked solution
(a)
A is the cell wall. It is made of cellulose and gives the cell a rigid, fixed shape, supporting the plant and stopping the cell bursting when it takes in a lot of water.
(b)
B is the cell (surface) membrane. It controls which substances can enter and leave the cell.
(c)
D is the (permanent) vacuole. It is filled with cell sap and stores water and nutrients, helping to keep the cell firm (turgid).
(d)
E is a chloroplast. It contains chlorophyll and is the site of photosynthesis, where the cell makes glucose using light energy.
QUESTION 3 2 marks Criterion A
Easy

State two structures that are found in a plant cell but are NOT found in an animal cell.

Show complete worked solution

Any two of: the cell wall, a large permanent vacuole, and chloroplasts. Both cell types share a nucleus, cytoplasm, cell membrane, mitochondria and ribosomes, but only plant cells have these three additional structures.

QUESTION 4 5 marks Criterion A
Medium

Answer the following about plant and animal cell structure.

a. Explain why plant cells can carry out photosynthesis but animal cells cannot.
[2]
b. Explain why a plant cell keeps a fixed, regular shape even when a lot of water enters it, while an animal cell in the same situation could burst.
[3]
Show complete worked solution
(a)
Plant cells contain chloroplasts, which contain the green pigment chlorophyll needed to absorb light energy for photosynthesis. Animal cells do not have chloroplasts, so they are unable to photosynthesise.
(b)
A plant cell is surrounded by a rigid cell wall made of cellulose, outside the cell membrane. As water enters, the cell swells and pushes against this strong wall, which resists the pressure and stops the cell from stretching further or bursting — the cell simply becomes firm (turgid). An animal cell has no cell wall, only a flexible cell membrane, so as water keeps entering there is nothing strong enough to resist the increasing pressure, and the membrane can eventually burst.
QUESTION 5 4 marks Criterion A
Medium

State the function of each of the following organelles.

a. The mitochondrion.
[2]
b. The ribosome.
[2]
Show complete worked solution
(a)
The mitochondrion is the site of (aerobic) respiration, which releases energy from glucose for the cell to use.
(b)
The ribosome is the site of protein synthesis — it is where the cell builds proteins.
QUESTION 6 7 marks Criterion A
Hard

Root cells (found underground) and leaf palisade cells (found inside a leaf) are both plant cells, and both contain a nucleus, cytoplasm, a cell membrane and a cell wall.

a. Suggest why root cells do not contain chloroplasts, even though they are plant cells.
[3]
b. Root hair cells actively absorb mineral ions from the soil, often against a concentration gradient (active transport). Predict how the number of mitochondria in a root hair cell might compare to an average plant cell, and explain your reasoning.
[4]
Show complete worked solution
(a)
Root cells are underground, so no light reaches them. Chloroplasts are only useful for photosynthesis, which requires light — since there is no light available for a root cell to use, it has no need to build or maintain chloroplasts, which would simply waste the cell's resources.
(b)
A root hair cell is likely to contain more mitochondria than an average plant cell. Absorbing mineral ions by active transport (against a concentration gradient) requires energy, unlike simple diffusion. Since mitochondria are the site of respiration and release this energy from glucose, a cell that needs to carry out a lot of active transport would need more mitochondria to supply the extra energy demand.
QUESTION 7 3 marks Criterion A
Medium

Explain why the cell is described as “the basic unit of life”, according to cell theory.

Show complete worked solution

Cell theory states that all living organisms are made up of one or more cells, and that the cell is the smallest unit that can carry out all the processes needed for life (such as respiration, growth and reproduction) on its own. Because nothing smaller than a complete cell can independently carry out all of these life processes, the cell is considered the basic (smallest) structural and functional unit of every living thing.

QUESTION 8 7 marks Criterion B
Medium

A student wants to compare the structures visible in plant cells and animal cells by preparing and observing an onion epidermis cell sample (stained with iodine solution) and a human cheek cell sample (stained with methylene blue) under a light microscope.

a. State the independent variable and the dependent variable in this investigation.
[2]
b. State two variables that should be kept the same (controlled) for a fair comparison, and explain why for one of them.
[3]
c. Describe how the student should prepare a temporary mount slide of the onion cells before viewing.
[2]
Show complete worked solution
(a)
Independent variable: the type of cell (plant/onion cell vs. animal/cheek cell). Dependent variable: which structures are visible when each sample is observed.
(b)
Controlled variables could include the magnification used to view each slide, and the amount/concentration of stain added. Why control magnification: using a different magnification for each slide would make it harder to fairly judge how much detail is visible in each cell type, since a higher magnification alone could reveal extra structures unrelated to any real difference between plant and animal cells.
(c)
Peel a thin, single layer of epidermis from the inside of an onion scale, lay it flat on a microscope slide, add a drop of water or iodine solution, then lower a coverslip on top at an angle using a mounted needle, to avoid trapping air bubbles.
QUESTION 9 6 marks Criterion B
Medium

When preparing a wet mount slide of cheek cells, a student notices dark, round bubbles trapped under the coverslip that could easily be mistaken for cell structures.

a. Explain why air bubbles are a problem for this investigation.
[2]
b. Describe how the coverslip should be lowered onto the slide to avoid trapping air bubbles.
[2]
c. Suggest one further improvement that would make the comparison between plant and animal cells more reliable overall.
[2]
Show complete worked solution
(a)
Air bubbles can be mistaken for cell structures (such as nuclei or vacuoles) when viewed under the microscope, which could lead to inaccurate observations, drawings, or identifications, reducing the reliability of the results.
(b)
The coverslip should be lowered slowly and at an angle (about 45°), using a mounted needle to guide one edge down first, letting the coverslip fall gradually so trapped air can escape, rather than dropping it flat onto the slide.
(c)
Prepare and examine several slides (or several fields of view on the same slide) of each cell type, rather than relying on just one observation, and/or have more than one student independently identify the visible structures and compare their results.
QUESTION 10 8 marks Criterion B
Hard

A student claims: “All plant cells contain chloroplasts, and all animal cells lack a cell wall.” They plan to test this by examining prepared slides of 6 different plant tissues and 6 different animal tissues under a microscope.

a. Evaluate whether examining only 6 plant tissue types is a large enough sample to support a general conclusion about all plant cells. Justify your answer.
[3]
b. Suggest one way the sampling method could be improved to make the conclusion more reliable.
[2]
c. The student actually examines only cells from green leaves for all 6 of their ‘plant’ samples, and finds chloroplasts in every one. Explain why this specific choice of samples would lead to a misleading conclusion about ALL plant cells.
[3]
Show complete worked solution
(a)
Six samples is not a large enough sample. Plants contain many different tissue types (for example root, stem, petal and seed tissue) and many of these — such as root cells, which never receive light — do not contain chloroplasts. A sample of only 6 tissues cannot represent the full diversity of plant cells, so a conclusion based on it risks being wrong for tissue types that were not tested, especially if the tissues chosen happen not to be representative.
(b)
Deliberately choose a wide, varied range of tissue types (for example including root, stem, seed and petal tissue, not just leaves), and examine several individual cells within each tissue sample, rather than relying on a single narrow group of similar tissues.
(c)
Leaves are specifically adapted for photosynthesis and are the plant tissue most likely to contain chloroplasts, so choosing only leaf samples strongly biases the investigation towards finding chloroplasts. The resulting claim that “all plant cells contain chloroplasts” would incorrectly generalise from this narrow, unrepresentative sample — many other plant cells, such as root or petal cells, commonly lack chloroplasts, so the conclusion would not hold for the plant as a whole.
QUESTION 11 3 marks Criterion C
Easy

The table shows which structures were observed in two unidentified cell samples viewed under a microscope.

StructureSample 1Sample 2
Nucleus??
Cell wall??
Chloroplast??
Large (permanent) vacuole??
Mitochondria??
a. Based on the table, which sample is most likely an animal cell? Explain your answer using the data.
[2]
b. Identify which sample is a plant cell.
[1]
Show complete worked solution
(a)
Sample 1. It lacks a cell wall, chloroplast and large vacuole — structures found only in plant cells — while still having a nucleus and mitochondria, which both cell types share.
(b)
Sample 2, since it shows a cell wall, chloroplast and large vacuole, all of which are only found in plant cells.
QUESTION 12 2 marks Criterion C
Easy

The table shows the number of chloroplasts counted in five different plant cells viewed under a microscope.

Cell12345
Chloroplasts counted3028322629
Show complete worked solution

$$ \text{mean} = \frac{30+28+32+26+29}{5} = \frac{145}{5} $$

Answer: the mean number of chloroplasts per cell is $29$.

QUESTION 13 5 marks Criterion C
Medium

The table shows the number of nuclei counted in each of five plant cells viewed under a microscope.

Cell12345
Nuclei counted11121
a. Identify the anomalous result in this data.
[1]
b. Suggest one possible reason for this anomalous reading (other than a simple counting mistake).
[2]
c. State what a student should do with this reading before calculating a mean number of nuclei per cell.
[2]
Show complete worked solution
(a)
Cell 4, which shows 2 nuclei, is anomalous.
(b)
The cell may have been caught in the middle of cell division (mitosis), a brief stage where the genetic material has already copied and the nucleus has started to divide, meaning two nuclei could genuinely be visible for a short time.
(c)
The anomalous reading should be excluded (or investigated further, e.g. by checking the cell again) before it is used to calculate a mean, since including it could distort the average away from the typical value of one nucleus per cell.
QUESTION 14 5 marks Criterion C
Medium

The table shows the diameter of the nucleus, measured in five different cells from the same tissue sample.

Cell12345
Nucleus diameter (?m)8.28.58.18.48.3
a. Calculate the mean nucleus diameter.
[2]
b. Explain why measuring the diameter of five different cells, rather than just one, gives a more reliable estimate of the typical nucleus size.
[3]
Show complete worked solution
(a)
$$ \text{mean} = \frac{8.2+8.5+8.1+8.4+8.3}{5} = \frac{41.5}{5} = 8.3\,\mu\text{m} $$
(b)
Individual cells naturally vary slightly in size, so a single measurement could happen to be unusually large or small purely by chance, or affected by a small measuring error. Taking several measurements and averaging them reduces the effect of this natural variation and random error, giving a value that better represents the typical (true) nucleus size for this cell type.
QUESTION 15 5 marks Criterion C
Medium

The table shows whether certain structures were seen in three different cell samples.

StructureOnion epidermis cellElodea (pondweed) leaf cellHuman cheek cell
Nucleus???
Cell wall???
Chloroplast???
Vacuole? (large)? (large)?
a. Explain why the onion epidermis cell shows a cell wall and vacuole but no chloroplasts, even though it is a plant cell.
[2]
b. Using the table, explain how you could tell, from structure alone, that the Elodea cell (but not the onion cell) is adapted for photosynthesis.
[3]
Show complete worked solution
(a)
The onion epidermis is a layer inside the bulb, which grows underground and does not receive light. Like a root cell, it has no way to photosynthesise, so — despite being a plant cell with a cell wall and vacuole — it has no need for chloroplasts and does not contain them.
(b)
The Elodea cell contains chloroplasts, which the onion cell lacks. Chloroplasts are the site of photosynthesis, so only a cell containing them — like the Elodea leaf cell, which grows exposed to light — is structurally adapted to photosynthesise; the onion cell, without chloroplasts, is not.
QUESTION 16 5 marks Criterion C
Medium

A textbook states: “plant cells are always bigger than animal cells.” A student collects data: the mean diameter of 10 onion epidermis cells measured $120\,\mu\text{m}$; the mean diameter of 10 human cheek cells measured $40\,\mu\text{m}$.

a. Does this data support the textbook's claim? Explain your answer, using the numbers.
[2]
b. Explain why this data alone is NOT enough evidence to conclude that ALL plant cells are always bigger than ALL animal cells.
[3]
Show complete worked solution
(a)
Yes, this particular data supports the claim: the onion (plant) cells measured, on average, $3$ times larger than the cheek (animal) cells ($120\,\mu\text{m}$ compared with $40\,\mu\text{m}$).
(b)
Only one type of plant cell (onion) and one type of animal cell (cheek) were compared. There is huge variation in cell size within both plants and animals — for example, some plant cells such as pollen grains are tiny, while some animal cells such as a human egg cell can be relatively large — so a single pairwise comparison cannot support a claim about “all” cells of each type. A much wider, more representative sample of many different cell types would be needed to support such a general conclusion.
QUESTION 17 8 marks Criterion C
Hard

Four students each examined the same prepared slide of leaf tissue and counted how many of 50 cells in their field of view contained visible chloroplasts.

StudentABCD
Cells with chloroplasts (out of 50)38411239
a. Calculate the percentage of counted cells containing visible chloroplasts for each student.
[3]
b. Identify which student's result is anomalous, and suggest one likely explanation for their result.
[2]
c. Explain how the class could combine all four students' data to produce a more reliable final estimate, and calculate this value, excluding the anomalous result.
[3]
Show complete worked solution
(a)

A: $\dfrac{38}{50}\times100=76\%$   B: $\dfrac{41}{50}\times100=82\%$   C: $\dfrac{12}{50}\times100=24\%$   D: $\dfrac{39}{50}\times100=78\%$

(b)
Student C (24%) is anomalous, much lower than the other three (76-82%). A likely explanation is that Student C may have viewed a different, non-photosynthetic part of the tissue by mistake (for example a vein or a deeper, shaded cell layer), or made a counting/identification error.
(c)

Averaging several independent counts reduces the effect of any one student's individual error or an unrepresentative field of view, giving a more reliable overall estimate than relying on a single count. Excluding Student C's anomalous result:

$$ \text{mean} = \frac{76+82+78}{3} = \frac{236}{3} = 78.7\% \ (\text{3 s.f.}) $$

QUESTION 18 4 marks Criterion D
Medium

Scientists can now grow “cultured” (lab-grown) meat by taking a small sample of muscle cells from a living animal and growing them in a nutrient-rich liquid in a lab, without raising and slaughtering a whole animal.

Discuss one benefit and one drawback of this technology.

Show complete worked solution

Benefit: because a whole animal does not need to be raised and slaughtered, cultured meat could greatly reduce the farmland, water and animal feed currently used for livestock farming, while also reducing animal suffering, all while still producing real animal muscle cells for meat.

Drawback: the technology to grow cells at a large enough scale is currently very expensive and energy-intensive, meaning cultured meat costs far more than farmed meat and is not yet widely available or affordable; some consumers may also be reluctant to eat lab-grown food, limiting how much difference it can make in the short term.

QUESTION 19 6 marks Criterion D
Hard

Because a single plant cell can, under the right conditions, divide and develop into a whole new plant (a property most animal cells do not have), scientists use “tissue culture” to grow thousands of genetically identical clones of a high-yielding or disease-resistant crop plant from just a few starting cells.

Discuss one benefit and one drawback of using this technology to produce crops.

Show complete worked solution

Benefit: tissue culture allows farmers to rapidly produce huge numbers of identical, high-quality plants with desirable traits (such as disease resistance or high yield), much faster and more consistently than traditional breeding, which can improve food security and crop reliability.

Drawback: because all of the cloned plants are genetically identical, a field of clones has no genetic diversity. If a new disease or pest evolves that can attack that particular genetic variety, it could wipe out the entire crop, since no plants in the field would carry natural resistance — unlike a genetically varied population, where some plants might survive and the crop as a whole would not be lost.

QUESTION 20 6 marks Criterion D
Hard

Plant cell walls are made mostly of cellulose, a tough carbohydrate. Scientists can break down cellulose from waste plant material (such as stalks and husks left over after harvest) and ferment it to produce bioethanol, a fuel that can replace some petrol/diesel in vehicles.

Discuss one benefit and one drawback of producing fuel this way.

Show complete worked solution

Benefit: bioethanol is made from renewable plant material, and can use waste crop parts that would otherwise be thrown away. Because the plants absorbed carbon dioxide as they grew, burning this fuel can release less net carbon dioxide than burning a fossil fuel, helping reduce its overall contribution to climate change.

Drawback: breaking down tough cellulose requires significant processing, energy, and often specific enzymes or technology, which is currently expensive. If crops are grown deliberately for fuel rather than only using waste material, this can compete with food production for farmland and water, potentially raising food prices or reducing food security in some regions.

Using Microscopes 20 questions

QUESTION 1 5 marks Criterion A
Easy
A B C D E

The diagram shows a light microscope, with five parts labelled A-E.

a. Identify part A.
[1]
b. Identify part B.
[1]
c. Identify part C.
[1]
d. Identify part D.
[1]
e. Identify part E.
[1]
Show complete worked solution
(a)
A is the eyepiece lens.
(b)
B is an objective lens.
(c)
C is the stage (where the slide is placed).
(d)
D is the light source (lamp or mirror).
(e)
E is a focusing knob (coarse or fine focus).
QUESTION 2 2 marks Criterion A
Easy

Explain why you should always start viewing a specimen under the LOWEST-power objective lens first, before switching to a higher-power lens.

Show complete worked solution

The lowest-power lens gives the widest field of view, making it much easier to locate the specimen on the slide. It also keeps the objective lens further from the slide, reducing the risk of the lens touching and damaging the slide (and specimen) when first focusing.

QUESTION 3 3 marks Criterion A
Medium

A microscope has an eyepiece lens of magnification $\times10$ and is set to use an objective lens of magnification $\times100$. Calculate the total magnification being used.

Show complete worked solution

Step 1 — State the formula:

$$ \text{total magnification} = \text{eyepiece magnification} \times \text{objective magnification} $$

Step 2 — Substitute and calculate:

$$ 10 \times 100 = 1000 $$

Answer: total magnification $= \times1000$

QUESTION 4 4 marks Criterion A
Medium

State the function of each of the following microscope parts.

a. The coarse focus knob.
[1]
b. The fine focus knob.
[1]
c. The light source.
[1]
d. The stage clips.
[1]
Show complete worked solution
(a)
Moves the stage (or tube) up and down quickly, to bring the specimen roughly into focus.
(b)
Makes small, precise adjustments to sharpen the focus once the specimen is roughly in view.
(c)
Illuminates the specimen from below, so light can pass through it and it can be seen clearly.
(d)
Hold the slide firmly in place on the stage so it does not slip or move while being viewed.
QUESTION 5 3 marks Criterion A
Medium

Explain why specimens viewed under a light microscope are usually cut into very thin slices before being placed on a slide.

Show complete worked solution

A light microscope works by shining light up through the specimen and lenses to the eye, so light needs to be able to pass through the specimen. A thin slice lets light through clearly, and avoids overlapping layers of cells sitting on top of one another, which would make the image blurry and much harder to interpret.

QUESTION 6 3 marks Criterion A
Medium

A student sets up a microscope with a $\times15$ eyepiece lens and can choose between $\times4$, $\times10$ and $\times40$ objective lenses.

Show complete worked solution

The highest total magnification uses the eyepiece with the highest-power objective lens available:

$$ 15 \times 40 = 600 $$

Answer: the highest total magnification available is $\times600$.

QUESTION 7 4 marks Criterion A
Hard

Explain the difference between magnification and resolution.

a. Define magnification.
[2]
b. Define resolution.
[2]
Show complete worked solution
(a)
Magnification is how many times larger an image appears compared with the real (actual) size of the object.
(b)
Resolution is the ability to distinguish (see as two separate points) two objects that are very close together — in other words, the amount of fine detail that can be seen clearly, rather than as a single blurred point.
QUESTION 8 6 marks Criterion B
Medium

A student wants to investigate whether the length of time a specimen is left in iodine stain affects how clearly its structures can be seen under a microscope.

a. State the independent and dependent variables.
[2]
b. State two variables that must be controlled for this to be a fair test.
[2]
c. Suggest how the student could make their measure of ‘clarity’ more objective and reliable, rather than just one person's opinion.
[2]
Show complete worked solution
(a)
Independent variable: staining time (e.g. $30\,\text{s}$, $1$, $2$ and $5$ minutes). Dependent variable: clarity of the structures visible (for example, the number of structures that can be clearly identified).
(b)
For example: the same type and thickness of specimen used each time, and the same magnification and light intensity used to view each slide.
(c)
Have several different students independently rate the clarity on the same numerical scale (or independently count the number of distinct structures they can identify) at each staining time, and use the average of their scores, rather than relying on a single person's personal judgement.
QUESTION 9 6 marks Criterion B
Medium

A student measures the diameter of an onion cell using a microscope fitted with an eyepiece graticule (a tiny built-in ruler), repeating the measurement on three different cells: $42\,\mu\text{m}$, $58\,\mu\text{m}$, $45\,\mu\text{m}$.

a. Explain why the student should measure several different cells, rather than just one.
[2]
b. The $58\,\mu\text{m}$ measurement seems unusually high. Suggest one reason why measuring cell diameter under a microscope can be inaccurate.
[2]
c. Suggest one improvement to make this measurement more reliable.
[2]
Show complete worked solution
(a)
Individual cells vary naturally in size, so a single measurement might not be typical. Measuring several cells and averaging the results reduces the effect of this natural variation and gives a more reliable estimate of the typical cell size.
(b)
The cell being measured might not be lying flat in the plane of focus (making it look wider than it is), the graticule scale might have been misread, or the student may have accidentally measured across two overlapping cells instead of one.
(c)
Measure a much larger number of cells (e.g. $10$ or more) and calculate a mean, and/or have the measurements independently checked or repeated by a second student.
QUESTION 10 8 marks Criterion B
Hard

A school with limited funding builds a simple “smartphone microscope” by taping a small lens over a phone camera, and wants to test whether it is reliable enough to replace their proper light microscopes for measuring cell sizes.

a. Suggest a method for testing whether the smartphone microscope gives measurements that agree with the school's existing light microscope.
[3]
b. State one variable that must be kept the same across both sets of measurements for this to be a fair comparison.
[2]
c. Explain what result would show that the smartphone microscope is NOT reliable enough to replace the light microscope.
[3]
Show complete worked solution
(a)
Measure the same specimen (for example, the same slide of onion cells, or an object of known size) using both instruments, taking several repeated measurements with each, and then compare the two sets of measurements (or their means).
(b)
The same specimen/slide (and the same magnification or scale reference) must be used for measurements taken with both instruments.
(c)
If repeated measurements taken with the smartphone microscope vary widely from each other (are inconsistent), or if its mean measurement differs substantially and consistently from the light microscope's mean (which is the trusted, properly calibrated standard), this would show the smartphone microscope is not accurate or reliable enough to replace it for scientific measurements.
QUESTION 11 2 marks Criterion C
Easy

A drawing of a cell is $20\,\text{mm}$ long. The actual cell is $0.1\,\text{mm}$ long. Calculate the magnification of the drawing.

Show complete worked solution

$$ \text{magnification} = \frac{\text{image size}}{\text{actual size}} = \frac{20}{0.1} $$

Answer: magnification $= \times200$ (magnification has no unit, since it is a ratio of two lengths).

QUESTION 12 3 marks Criterion C
Easy

An image of an onion cell is measured as $15\,\text{mm}$ wide. The drawing was made at a magnification of $\times150$.

a. Calculate the actual width of the cell in mm.
[2]
b. Convert your answer to micrometres ($1\,\text{mm}=1000\,\mu\text{m}$).
[1]
Show complete worked solution
(a)
$$ \text{actual size} = \frac{\text{image size}}{\text{magnification}} = \frac{15}{150} = 0.1\,\text{mm} $$
(b)
$$ 0.1 \times 1000 = 100\,\mu\text{m} $$
QUESTION 13 4 marks Criterion C
Medium
Drawn (image) length = 60 mm

A student draws a red blood cell as part of a scientific diagram, measured below. The actual diameter of a red blood cell is about $0.007\,\text{mm}$.

a. Convert the drawn width from cm to mm (the drawing measures $6\,\text{cm}$ across).
[1]
b. Calculate the magnification of this drawing. Give your answer to an appropriate number of significant figures.
[3]
Show complete worked solution
(a)
$6\,\text{cm} = 60\,\text{mm}$
(b)

$$ \text{magnification} = \frac{\text{image size}}{\text{actual size}} = \frac{60}{0.007} = 8571.43\ldots $$

Answer: magnification $\approx \times8570$ (3 s.f.)

QUESTION 14 5 marks Criterion C
Medium

The same cell was drawn three times, at three different magnifications. The table shows the image size measured each time.

Magnification used×100×200×400
Image size (mm)51020
a. Calculate the actual size of the cell using the data at each magnification, and show that all three give a consistent answer.
[3]
b. Explain why obtaining a consistent actual size from three different magnifications increases confidence in the result.
[2]
Show complete worked solution
(a)

$$ \text{actual size} = \frac{\text{image size}}{\text{magnification}} $$

$\times100$: $\dfrac{5}{100}=0.05\,\text{mm}$   $\times200$: $\dfrac{10}{200}=0.05\,\text{mm}$   $\times400$: $\dfrac{20}{400}=0.05\,\text{mm}$

All three calculations give the same actual size of $0.05\,\text{mm}$ ($50\,\mu\text{m}$).

(b)
If the three magnifications had given very different ‘actual size’ answers, this would suggest a measurement or calculation error somewhere. The fact that all three independent calculations agree supports that $0.05\,\text{mm}$ is genuinely the cell's true size, rather than the result of a mistake.
QUESTION 15 5 marks Criterion C
Medium

Four students each measured the same type of cell at a different magnification, then used the magnification formula to calculate its actual size.

StudentImage size measuredMagnification usedCalculated actual size
A40 mm×2000.2 mm
B4 cm×2000.02 mm
C60 mm×3000.2 mm
D30 mm×1500.2 mm
a. Identify which student's calculated actual size does not match the others.
[1]
b. Student B measured their image as $4\,\text{cm}$ but used the magnification formula without converting units first. Show the correct calculation for Student B's actual cell size, in mm.
[3]
c. Explain why image size and actual size must be given in the SAME units before using the magnification formula.
[1]
Show complete worked solution
(a)
Student B — they calculated $0.02\,\text{mm}$, while the others all calculated $0.2\,\text{mm}$.
(b)

Convert first: $4\,\text{cm} = 40\,\text{mm}$.

$$ \text{actual size} = \frac{40}{200} = 0.2\,\text{mm} $$

This now matches the other three students' results of $0.2\,\text{mm}$.

(c)
Magnification is a ratio of two lengths, with no unit of its own — mixing units (such as cm with mm) without converting makes the calculated actual size (or magnification) wrong by exactly the conversion factor between those units, even though the arithmetic itself was done correctly.
QUESTION 16 4 marks Criterion C
Medium

Under a certain magnification, the circular field of view of a microscope has a diameter of $1.5\,\text{mm}$. Approximately $30$ identical plant cells fit side by side across this diameter.

a. Estimate the actual width of one cell, in mm, showing your working.
[3]
b. Convert your answer to micrometres.
[1]
Show complete worked solution
(a)
$$ \text{width of one cell} = \frac{\text{field of view diameter}}{\text{number of cells across it}} = \frac{1.5}{30} = 0.05\,\text{mm} $$
(b)
$$ 0.05 \times 1000 = 50\,\mu\text{m} $$
QUESTION 17 7 marks Criterion C
Hard

A student is asked to determine the actual length of a plant cell. They measure their drawing as $8.4\,\text{cm}$ long, using a ruler that can be read to the nearest $0.1\,\text{cm}$. The drawing was made using a microscope set to an eyepiece magnification of $\times10$ and an objective magnification of $\times40$.

a. Calculate the total magnification used.
[1]
b. Convert the drawing length to mm, then calculate the actual length of the cell in mm. Give your answer to an appropriate number of significant figures.
[4]
c. The ruler can only be read to the nearest $0.1\,\text{cm}$ ($1\,\text{mm}$). Explain how this limits the precision of the final actual-size answer, even though the calculation itself is exact.
[2]
Show complete worked solution
(a)
$$ 10 \times 40 = \times400 $$
(b)

$8.4\,\text{cm} = 84\,\text{mm}$

$$ \text{actual size} = \frac{84}{400} = 0.21\,\text{mm} $$

Answer: actual length $\approx 0.21\,\text{mm}$ (2 s.f.)

(c)
Because the drawing length is only known to the nearest $1\,\text{mm}$ (an uncertainty of about $\pm0.5\,\text{mm}$), the calculated actual size inherits this same relative uncertainty, just scaled down by the magnification. The final answer of $0.21\,\text{mm}$ can therefore only really be trusted to about $2$ significant figures — writing more decimal places would give a false impression of precision beyond what the original ruler measurement can actually support.
QUESTION 18 4 marks Criterion D
Medium

Electron microscopes can magnify specimens far more than light microscopes (up to about 2 million times, compared to around 1500 times for a typical light microscope) and can reveal much finer detail, allowing scientists to see structures such as viruses and individual organelles clearly.

Discuss one benefit and one drawback of using an electron microscope compared to a light microscope.

Show complete worked solution

Benefit: the far higher magnification and resolution of an electron microscope reveals fine detail — such as viruses and the internal structure of organelles — that is completely invisible under a light microscope, hugely advancing medical research and diagnosis.

Drawback: electron microscopes are extremely expensive and require the specimen to be placed in a vacuum, usually after being specially treated or coated, which kills the specimen. This means living processes cannot be observed happening in real time, unlike with a light microscope, and the cost and size of electron microscopes make them unavailable in most schools and smaller laboratories.

QUESTION 19 6 marks Criterion D
Hard

Scientists have developed cheap, portable microscope attachments that clip onto a smartphone camera, allowing health workers in remote areas with limited resources to examine blood samples under magnification, photograph what they see, and send the images to specialists elsewhere for diagnosis (for example, of malaria).

Evaluate the impact of this technology, discussing both a benefit and a limitation.

Show complete worked solution

Benefit: this makes microscopic diagnosis available in remote or low-resource communities that could never afford or access a full laboratory microscope, potentially enabling much faster diagnosis and treatment of diseases such as malaria, and saving lives in areas far from specialist doctors and hospitals.

Limitation: the image quality, magnification and resolution from a simple clip-on lens is far lower than a proper light or electron microscope, so subtle structures or early-stage infections could be missed or misdiagnosed. The system also still relies on a working smartphone, a signal or internet connection to send images, and a specialist being available to interpret them — none of which may be reliably available in the same remote areas that need this technology most.

QUESTION 20 6 marks Criterion D
Hard

Before microscopes were invented, nobody could see bacteria, and diseases were often blamed on “bad air” or evil spirits. The invention and improvement of microscopes allowed scientists to see microorganisms directly for the first time, eventually leading to germ theory and much of modern medicine (including vaccines and antibiotics).

Discuss the impact of the invention of the microscope on society, including one benefit and one possible concern or limitation.

Show complete worked solution

Benefit: directly seeing microorganisms let scientists finally identify the true causes of many diseases, leading to hygiene practices (such as hand-washing and sterilising medical equipment), vaccines and antibiotics that have saved an enormous number of lives and increased average life expectancy worldwide.

Concern/limitation: a light microscope alone still cannot show viruses, which are far too small to see even at its maximum magnification, so some diseases remained mysterious and hard to diagnose until the much later invention of the electron microscope. Access to microscopes, and to the trained scientists needed to use them, has also historically been — and in some poorer regions still is — unequal around the world, meaning the medical benefits of this technology have not reached everyone equally.

Specialised Cells 20 questions

QUESTION 1 5 marks Criterion A
Easy
A B C D E

The diagram shows a neuron (nerve cell), with five structures labelled A-E.

a. Identify structure A, and state its function.
[1]
b. Identify structure B.
[1]
c. Identify structure C, and state its function.
[1]
d. Identify structure D, and state its function.
[1]
e. Identify structure E.
[1]
Show complete worked solution
(a)
A is a dendrite. Dendrites receive nerve impulses from other neurons.
(b)
B is the cell body, which contains the nucleus.
(c)
C is the axon — a long fibre that carries the nerve impulse away from the cell body.
(d)
D is the myelin sheath — a fatty layer that insulates the axon and speeds up the nerve impulse.
(e)
E is the axon terminals, which pass the impulse on to the next neuron or an effector (e.g. a muscle).
QUESTION 2 2 marks Criterion A
Easy

State two ways in which a (mammalian) red blood cell is adapted for carrying oxygen efficiently.

Show complete worked solution

Any two of: it has no nucleus, leaving more space inside the cell for haemoglobin (and therefore for carrying oxygen); it has a biconcave disc shape, which increases its surface area for gas exchange; and it is packed with haemoglobin, a protein that binds to oxygen.

QUESTION 3 4 marks Criterion A
Medium

A sperm cell is specialised for reaching and fertilising an egg cell.

a. Describe how the tail (flagellum) of a sperm cell adapts it for its function.
[2]
b. Describe how the large number of mitochondria packed into the mid-piece of a sperm cell adapts it for its function.
[2]
Show complete worked solution
(a)
The long tail whips from side to side, propelling the sperm cell forwards, helping it swim through fluid to reach and fertilise an egg cell.
(b)
The mitochondria carry out respiration, releasing the energy needed to power the constant movement of the tail over the relatively long swim towards the egg cell.
QUESTION 4 5 marks Criterion A
Medium
A B

The diagram shows a root hair cell, with two structures labelled A and B.

a. Identify structure A, and explain how it adapts the cell for absorbing water and minerals from the soil.
[3]
b. Explain why root hair cells do not contain chloroplasts.
[2]
Show complete worked solution
(a)
A is the root hair — a long, thin extension of the cell surface. It greatly increases the cell's surface area in contact with the surrounding soil, allowing more water and mineral ions to be absorbed into the cell in a given time.
(b)
Root hair cells are found underground, where no light can reach them. Since photosynthesis is impossible without light, the cell has no use for chloroplasts, so it does not produce or maintain them.
QUESTION 5 4 marks Criterion A
Medium

Palisade mesophyll cells are found near the upper surface of a leaf, and are the main site of photosynthesis in a plant.

a. State two structural features of a palisade cell that adapt it for photosynthesis.
[2]
b. Explain why palisade cells are positioned near the TOP of the leaf rather than near the bottom.
[2]
Show complete worked solution
(a)
Any two of: it contains many (large) chloroplasts, packed near the top of the cell; and it has an elongated, column-like shape, which allows many palisade cells to be packed closely and upright just under the leaf surface.
(b)
The upper surface of a leaf receives the most direct sunlight. Positioning the photosynthesising cells there means they can absorb the maximum amount of light for photosynthesis.
QUESTION 6 4 marks Criterion A
Medium

Muscle cells are specialised for contraction (movement).

a. State one structural feature of a muscle cell, other than having many mitochondria, that adapts it for its function.
[2]
b. Explain why muscle cells contain an unusually large number of mitochondria.
[2]
Show complete worked solution
(a)
It contains many protein filaments arranged along its length, which can slide past one another to shorten the cell and cause contraction. (Its elongated shape also allows the whole cell to contract along its length.)
(b)
Contraction requires a lot of energy. Mitochondria are the site of (aerobic) respiration, which releases this energy from glucose, so a large number of mitochondria allow the cell to generate enough energy to sustain repeated contraction.
QUESTION 7 6 marks Criterion A
Hard

All the specialised cells you have studied (e.g. nerve cells, sperm cells, root hair cells, red blood cells) develop from unspecialised cells that all originally contained the same genetic information (DNA), through a process called differentiation.

a. Explain what is meant by ‘cell differentiation’.
[2]
b. A red blood cell loses its nucleus as it matures, but a nerve cell keeps its nucleus for its entire life. Suggest why a nerve cell needs to keep its nucleus while a red blood cell does not.
[4]
Show complete worked solution
(a)
Cell differentiation is the process by which unspecialised cells develop different structures and functions to become specialised for a particular role, even though they all contain the same genes/DNA — different genes are switched on (or off) in different cell types.
(b)
A nerve cell can live for a person's entire lifetime and must be able to keep making proteins for repair, maintenance and communication (for example, producing chemicals for signalling) throughout that time, so it needs to keep its DNA/nucleus in order to keep giving these instructions. A red blood cell has a much simpler, short-term job (carrying oxygen) and a short lifespan (around 4 months); losing its nucleus frees up extra internal space for more haemoglobin, increasing its oxygen-carrying capacity, and since it does not need to make new proteins or divide, it does not need to keep its DNA.
QUESTION 8 6 marks Criterion B
Medium

A student investigates whether the number of root hairs on a plant root affects the rate at which the plant takes up water, using cress seedlings grown in two different conditions (one group with root hairs intact, one group with root hairs gently rubbed off).

a. State a suitable independent variable and dependent variable for this investigation.
[2]
b. State two variables that should be controlled, and explain why for one of them.
[2]
c. Describe a method for measuring the rate of water uptake in this investigation.
[2]
Show complete worked solution
(a)
Independent variable: whether root hairs are present (intact vs. removed). Dependent variable: rate of water uptake (for example, the volume of water taken up per hour).
(b)
For example: the size/age of seedling used, and the temperature and light level during the investigation. Why control temperature: a higher temperature increases the rate of water evaporation and uptake for reasons unrelated to root hairs, which would make the comparison between the two groups unfair.
(c)
Set up each seedling with its roots in a sealed container holding a known volume of water, with a thin layer of oil on top to prevent evaporation from the water surface itself. Measure the drop in water level (or the volume of water needed to top it back up) over a fixed time, such as 24 hours, for both groups, and compare.
QUESTION 9 6 marks Criterion B
Medium

A group of students is given five unlabelled prepared microscope slides, each showing a different specialised cell type (for example, a nerve cell, a red blood cell, a root hair cell, a sperm cell and a palisade cell), and must identify each cell type from its structure alone.

a. Explain why examining the actual slides under a microscope, rather than just looking at a single photograph of each cell, might make correct identification more reliable.
[2]
b. Suggest one way the investigation could be made fairer and more reliable, so that identification is not just guesswork.
[2]
c. Explain why it would be a problem for this investigation if some slides were viewed at a much higher magnification than others.
[2]
Show complete worked solution
(a)
A single photograph is fixed at one magnification and angle and may not clearly show every key identifying feature. Examining the real slide lets a student adjust the focus, magnification and viewing angle to check several identifying features before deciding, giving more information on which to base the identification.
(b)
Give students a reference key listing the structural features of each cell type (for example, ‘contains chloroplasts’ or ‘biconcave, no nucleus’) to check systematically against each slide, and/or have multiple students independently identify each slide and compare their answers before recording a final decision.
(c)
Viewing slides at different magnifications is not a fair, controlled comparison — key identifying details might only be easy to see on the higher-magnification slides simply because of the extra magnification, not because those cell types are genuinely easier to identify, making the test of identification skill unreliable.
QUESTION 10 8 marks Criterion B
Hard

A student hypothesises that plants grown in drier soil develop MORE root hairs per unit length of root than plants grown in consistently moist soil, as an adaptation to maximise water absorption.

a. Design a method to test this hypothesis, including the independent variable, the dependent variable, and how you would measure the dependent variable.
[4]
b. State three variables that must be controlled, and explain why controlling one of them matters for this specific investigation.
[3]
c. Explain one difficulty in reliably counting root hairs that this investigation might face, and how it could be addressed.
[1]
Show complete worked solution
(a)
Independent variable: soil moisture level (for example, watered daily vs. watered once a week). Dependent variable: number of root hairs per 1 cm length of root, measured by carefully removing a seedling, examining a 1 cm section of root under a microscope or hand lens, and counting the visible root hairs — repeated at several points along several roots in each group to improve reliability.
(b)
Controlled variables: the same plant species/seed batch, the same amount of light, and the same temperature and pot size. Example explanation: different plant species naturally produce different amounts of root hair regardless of soil moisture, so using the same species for both groups ensures that any difference seen is due to soil moisture and not an unrelated species difference.
(c)
Root hairs are extremely thin and delicate and are easily broken off when a seedling is pulled out of soil for examination, which could lead to undercounting. This could be addressed by very gently washing the soil away with a slow stream of water rather than pulling the root out, and by counting the hairs quickly before they dry out and shrivel.
QUESTION 11 3 marks Criterion C
Easy

The table shows the length of red blood cells measured in five blood smear samples.

Sample12345
Cell length (?m)7.27.57.17.47.3
a. Calculate the mean red blood cell length from this data.
[2]
b. A human red blood cell typically has a diameter of about 7-8 ?m. State whether this data is consistent with that typical value.
[1]
Show complete worked solution
(a)
$$ \text{mean} = \frac{7.2+7.5+7.1+7.4+7.3}{5} = \frac{36.5}{5} = 7.3\,\mu\text{m} $$
(b)
Yes — every individual reading ($7.1$-$7.5\,\mu\text{m}$) and the mean ($7.3\,\mu\text{m}$) fall within the expected $7$-$8\,\mu\text{m}$ range, so this data is consistent with the typical value.
QUESTION 12 3 marks Criterion C
Easy

A student examined a prepared blood smear slide and counted 200 cells in total, identifying the type of each one.

Cell typeRed blood cellsWhite blood cellsPlatelets
Number counted (out of 200)188102
a. Calculate the percentage of the counted cells that were red blood cells.
[2]
b. State which cell type was least common in this sample.
[1]
Show complete worked solution
(a)
$$ \frac{188}{200}\times100 = 94\% $$
(b)
Platelets (only $2$ out of $200$ counted).
QUESTION 13 5 marks Criterion C
Medium

The table shows the number of mitochondria counted in each of five muscle cell samples.

Sample12345
Mitochondria counted850910875120895
a. Identify the anomalous result.
[1]
b. Suggest a possible explanation for this anomalous result.
[2]
c. Calculate the mean number of mitochondria per cell, excluding the anomalous result.
[2]
Show complete worked solution
(a)
Sample 4 ($120$ mitochondria) is anomalous — far lower than the other four samples.
(b)
A damaged, immature or non-muscle cell may have been mistakenly counted, or a counting error may have occurred (for example, only part of the cell was within the field of view). It could also genuinely be a diseased cell with far fewer mitochondria than normal.
(c)
$$ \text{mean} = \frac{850+910+875+895}{4} = \frac{3530}{4} = 882.5 $$
QUESTION 14 5 marks Criterion C
Medium

The table shows the speed of nerve impulse conduction along four different nerve fibres.

FibreABCD
Myelinated?YesNoYesNo
Conduction speed (m/s)802601.5
a. Using the data, describe the relationship between whether a fibre is myelinated and its conduction speed.
[2]
b. Suggest why having some fast (myelinated) neurons is important for an animal's survival, giving an example.
[3]
Show complete worked solution
(a)
The myelinated fibres (A and C: $80$ and $60\,\text{m/s}$) conduct impulses far faster than the non-myelinated fibres (B and D: only $2$ and $1.5\,\text{m/s}$) — myelination is associated with a large increase (roughly $30$-$50\times$ in this data) in impulse speed.
(b)
Fast nerve impulses allow very rapid reactions, such as reflexes — for example, pulling a hand away from something hot, or reacting quickly to a predator. A delay of even a fraction of a second in transmitting such a signal could mean the difference between escaping danger safely and being injured, so fast-conducting myelinated neurons are especially important in reflex and danger-response pathways.
QUESTION 15 5 marks Criterion C
Medium

The table shows the approximate size of four human cell types.

Cell typeRed blood cellEgg cellNeuron cell bodyNeuron axon (longest, e.g. spinal cord to foot)
Approximate size7.5 ?m diameter120 ?m diameter20 ?m diameterup to 1 m long
a. Using the table, state which of these cell measurements is the smallest, and which is the largest.
[2]
b. Explain how a neuron can be described as microscopic in width but, in one dimension, remarkably long for a single cell — using the data to calculate how many times longer the longest axon is than a red blood cell's diameter.
[3]
Show complete worked solution
(a)
Smallest: the red blood cell diameter ($7.5\,\mu\text{m}$). Largest: the longest neuron axon (up to $1\,\text{m}$).
(b)

A neuron's cell body is microscopic, similar in size to other cells (only tens of ?m wide), but its axon is a long, extremely thin extension of that same single cell, which in some human neurons can reach up to about $1\,\text{m}$ ($1{,}000{,}000\,\mu\text{m}$) long.

$$ \frac{1{,}000{,}000}{7.5} \approx 133{,}000 $$

So the longest human axon is roughly $133{,}000$ times longer than a red blood cell's diameter, even though both cells are, in cross-section, similarly microscopic in width.

QUESTION 16 4 marks Criterion C
Medium

The table shows the number of root hairs counted in a fixed 1 cm section of root, for four different seedlings grown in the same conditions.

Seedling1234
Root hairs counted (per 1 cm)42394541
a. Calculate the mean number of root hairs per cm.
[2]
b. Explain why counting root hairs from four different seedlings, rather than just one, gives a more reliable estimate of the typical root hair density for this species.
[2]
Show complete worked solution
(a)
$$ \text{mean} = \frac{42+39+45+41}{4} = \frac{167}{4} = 41.75 $$
(b)
Different individual seedlings vary naturally. Averaging counts from several seedlings reduces the effect of this natural variation (and of any counting error in a single sample), giving a value that is more representative of the species as a whole.
QUESTION 17 7 marks Criterion C
Hard

The table shows the red blood cell count (millions per mm³ of blood) for a group of climbers, measured at sea level and again after 4 weeks living at high altitude, where oxygen is scarcer.

ClimberSea level countAfter 4 weeks at altitude
15.06.1
24.85.9
35.15.0
44.96.0
a. Calculate the percentage increase in red blood cell count for Climber 1.
[2]
b. Identify which climber's data does not fit the general pattern shown by the others, and describe the pattern the other three show.
[2]
c. Suggest a biological explanation for why the body increases red blood cell production at high altitude, and suggest one possible reason Climber 3's body did not show this response.
[3]
Show complete worked solution
(a)
$$ \frac{6.1-5.0}{5.0}\times100 = \frac{1.1}{5.0}\times100 = 22\% $$
(b)
Climber 3 does not fit the pattern (their count barely changed, from $5.1$ to $5.0$). The other three climbers all show a clear increase (of roughly $20$-$22\%$) in red blood cell count after 4 weeks at altitude.
(c)
At high altitude there is less oxygen in the air, so the body responds by producing more red blood cells, increasing the amount of haemoglobin available to carry oxygen and improving the blood's capacity to transport the scarce oxygen that is available. Climber 3 may not have fully acclimatised yet (adaptation can take longer in some individuals), may not have actually spent the full 4 weeks at altitude, or could have an underlying condition affecting red blood cell production — or their sea-level reading could itself have been unusually high to begin with.
QUESTION 18 4 marks Criterion D
Medium

Donated human blood relies on healthy red blood cells (and other blood components) from volunteer donors being collected, tested, stored, and given to patients who need transfusions after surgery, childbirth complications, or serious blood loss.

Discuss one benefit and one drawback/challenge of relying on human blood donation.

Show complete worked solution

Benefit: donated blood directly saves lives in emergencies, surgery, and for people with blood disorders, and — unlike many medical treatments — it is a relatively simple, low-cost way to help many patients using cells the body naturally makes.

Drawback: the blood supply depends entirely on enough healthy volunteers regularly donating, so shortages can occur, especially of rarer blood types or during crises when demand is high. Donated blood must also be carefully tested for infections before use, and it does not last indefinitely once stored, meaning it can go to waste if not used in time.

QUESTION 19 6 marks Criterion D
Hard

Stem cells are unspecialised cells that can still differentiate (develop) into many different types of specialised cell. Scientists are researching using stem cells to grow replacement specialised cells — for example, insulin-producing cells for people with diabetes, or nerve cells to help repair spinal cord injuries.

Evaluate the impact of this technology, discussing a benefit and a concern.

Show complete worked solution

Benefit: this could allow doctors to grow replacement cells or tissue for patients with currently incurable conditions — such as restoring damaged nerve cells after a spinal injury, or replacing insulin-producing cells destroyed by diabetes — potentially curing or greatly improving conditions that today can only be managed, and reducing reliance on donor organs/tissue, which are often in short supply.

Concern: some sources of stem cells, particularly from human embryos, raise ethical concerns for some people, since obtaining them can involve the destruction of a human embryo. The technology and treatments are also still expensive and not fully understood, meaning there is a risk of unintended effects (such as the new cells growing uncontrollably), and access to these advanced treatments may initially only be available to wealthier patients or countries, raising fairness concerns.

QUESTION 20 6 marks Criterion D
Hard

Some athletes have illegally used “blood doping” — for example, injecting themselves with extra red blood cells, or using a banned drug that makes the body produce more red blood cells — before an endurance event such as a marathon or cycling race, to increase the oxygen-carrying capacity of their blood.

Discuss why an athlete might be tempted to do this, and one serious drawback or risk of doing so.

Show complete worked solution

Reason/benefit (to the athlete): more red blood cells means more haemoglobin available to carry oxygen to the working muscles, which can significantly improve endurance performance, since muscles can respire aerobically for longer and more efficiently before fatiguing — potentially giving a real competitive advantage in a sport where races can be won or lost by fractions of a second.

Drawback/risk: blood doping is banned in almost all sports as a form of cheating, and athletes caught face bans, disqualification and damage to their reputation. Medically, an artificially high concentration of red blood cells makes the blood thicker (more viscous), which increases the risk of dangerous blood clots, strokes and heart problems, especially during intense exercise when the heart is already working hard — several documented athlete deaths have been linked to blood doping practices.