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MYP 3 · Science

Energy

100 questions across 5 sub-topics

Use the Sub-Topic filter above to focus on one.

Forms and Sources of Energy Energy Transfers and Transformations Conservation of Energy Work and Power (basic) Renewable vs Non-Renewable Resources

Forms and Sources of Energy 20 questions

QUESTION 1 3 marks Criterion A
Easy

Different objects and materials store or use energy in different forms.

a. A stretched bow used in archery stores energy. State the name of this form of energy.
[1]
b. The food an athlete eats provides energy for her muscles. State the form of energy stored in food.
[1]
c. A battery inside a torch stores energy. State the form of energy stored in a battery.
[1]
Show complete worked solution
(a)
Elastic potential energy — energy stored in an object when it is stretched or squashed.
(b)
Chemical (potential) energy — energy stored in the bonds between atoms in food, released by respiration.
(c)
Chemical (potential) energy — released as electrical energy when the battery is connected in a circuit.
QUESTION 2 2 marks Criterion A
Easy

A skateboarder of mass $40\,\text{kg}$ moves at a speed of $3\,\text{m/s}$. Calculate her kinetic energy. State the formula you use, show your substitution, and give your answer with the correct unit.

Show complete worked solution

Step 1 — State the formula:

$$ E_k = \tfrac{1}{2} m v^2 $$

Step 2 — Substitute the values:

$$ E_k = \tfrac{1}{2} \times 40 \times 3^2 $$

Step 3 — Calculate:

$$ E_k = \tfrac{1}{2} \times 40 \times 9 = 180 $$

Answer: $E_k = 180\,\text{J}$

QUESTION 3 2 marks Criterion A
Easy

A book of mass $1.5\,\text{kg}$ sits on a shelf $2\,\text{m}$ above the floor. Take $g = 10\,\text{N/kg}$. Calculate the gravitational potential energy (GPE) of the book relative to the floor.

Show complete worked solution

Step 1 — State the formula:

$$ E_p = m g h $$

Step 2 — Substitute:

$$ E_p = 1.5 \times 10 \times 2 $$

Answer: $E_p = 30\,\text{J}$

QUESTION 4 4 marks Criterion A
Medium

A trampolinist of mass $45\,\text{kg}$ bounces up and down on a trampoline.

a. At the highest point of her bounce she is briefly stationary. Name the main form of energy she has at this point.
[1]
b. At the lowest point of her bounce, where she is moving fastest, name the main form of energy she has (in addition to any energy stored in the trampoline itself).
[1]
c. At the lowest point she is moving at $4\,\text{m/s}$. Calculate her kinetic energy at this point.
[2]
Show complete worked solution
(a)
Gravitational potential energy — she is at maximum height and momentarily at rest, so she has no kinetic energy.
(b)
Kinetic energy — she is moving at her greatest speed at this point.
(c)
$$ E_k = \tfrac{1}{2} m v^2 = \tfrac{1}{2} \times 45 \times 4^2 = \tfrac{1}{2} \times 45 \times 16 = 360\,\text{J} $$
QUESTION 5 4 marks Criterion A
Medium

A crane lifts a steel beam of mass $250\,\text{kg}$ to a height of $12\,\text{m}$ above the ground. Take $g = 10\,\text{N/kg}$.

a. Calculate the GPE gained by the beam.
[2]
b. State your answer to (a) in kilojoules (kJ).
[1]
c. Is this energy now stored in the beam, or has it disappeared once the crane's engine stops lifting?
[1]
Show complete worked solution
(a)
$$ E_p = mgh = 250 \times 10 \times 12 = 30\,000\,\text{J} $$
(b)
$30\,000\,\text{J} \div 1000 = \textbf{30 kJ}$
(c)
It is now stored in the beam as gravitational potential energy — energy is transferred by the crane's engine to the beam, not created or destroyed, and stays stored until the beam is lowered or falls.
QUESTION 6 3 marks Criterion A
Medium

An $800\,\text{kg}$ roller-coaster car sits at the top of a hill, $20\,\text{m}$ above the lowest point of the track. Take $g = 10\,\text{N/kg}$. Calculate the gravitational potential energy of the car at the top of the hill. State the formula, show your substitution, and give the answer with the correct unit.

Show complete worked solution

$$ E_p = mgh = 800 \times 10 \times 20 $$

Answer: $E_p = 160\,000\,\text{J} = 160\,\text{kJ}$

QUESTION 7 6 marks Criterion A
Hard

A ball of mass $0.4\,\text{kg}$ is thrown and, at a certain instant, has $32\,\text{J}$ of kinetic energy.

a. State the formula for kinetic energy.
[1]
b. Rearrange the formula to make $v$ the subject.
[2]
c. Calculate the ball's speed at this instant, giving your answer to 3 significant figures.
[3]
Show complete worked solution
(a)
$$ E_k = \tfrac{1}{2} m v^2 $$
(b)
$$ E_k = \tfrac{1}{2} m v^2 \;\Rightarrow\; v^2 = \frac{2E_k}{m} \;\Rightarrow\; v = \sqrt{\frac{2E_k}{m}} $$
(c)
$$ v = \sqrt{\frac{2 \times 32}{0.4}} = \sqrt{\frac{64}{0.4}} = \sqrt{160} $$

Answer: $v = 12.6\,\text{m/s}$ (3 s.f.)

QUESTION 8 6 marks Criterion B
Medium

A student wants to compare the amount of chemical energy stored in two snack foods, a peanut and a crisp, by burning a sample of each under a test tube of water and measuring the temperature rise of the water.

a. State the independent and dependent variables in this investigation.
[2]
b. State two variables that should be controlled, and explain why for one of them.
[2]
c. Describe briefly how the student could use the results to compare the energy released by the two foods.
[2]
Show complete worked solution
(a)
Independent variable: type of food burned (peanut or crisp). Dependent variable: temperature rise of the water (used to estimate energy released).
(b)
Control the volume/mass of water used and the mass of the food sample burned each time. Why control the volume of water: a larger volume of water needs more energy to raise its temperature by the same amount, so an uncontrolled volume would make the temperature rises impossible to compare fairly.
(c)
Record the water's starting and final temperature for each food using a thermometer, and calculate the temperature rise for each. Since the mass of water and food sample are the same in both tests, the food producing the larger temperature rise can be judged to have released more chemical energy.
QUESTION 9 6 marks Criterion B
Medium

A student wants to investigate how the distance between a lamp and a solar panel affects the electrical energy the panel produces, measured using a voltmeter connected to the panel.

a. State the independent and dependent variables.
[2]
b. State one variable that should be controlled in this investigation, and explain why.
[2]
c. State one extra piece of equipment (other than the solar panel, lamp and voltmeter) that would help make the distance measurements more accurate, and explain how it is used.
[2]
Show complete worked solution
(a)
Independent variable: distance between the lamp and the solar panel. Dependent variable: voltage produced by the solar panel (a measure of electrical energy output).
(b)
Control the brightness/power setting of the lamp. If the lamp's brightness changed between readings, any difference in voltage could be caused by the change in brightness rather than the change in distance, making the test unfair.
(c)
A metre ruler or metre stick, placed between the lamp and the panel, used to measure and set each distance precisely (e.g. to the nearest millimetre) before each voltage reading is taken.
QUESTION 10 8 marks Criterion B
Hard

In the food-energy investigation above (burning a food sample to heat a test tube of water), a large amount of heat escapes into the surrounding air rather than heating the water, making the results unreliable.

a. Explain why this heat loss is a problem for comparing the two foods fairly.
[2]
b. Suggest a specific improvement to the method that would reduce this heat loss, and explain how it works.
[3]
c. Explain why repeating each test several times and calculating a mean would further improve the reliability of the results.
[3]
Show complete worked solution
(a)
If different amounts of heat escape during each test (for example due to draughts, or the flame being a different distance from the tube each time), the temperature rise no longer accurately reflects the true energy content of the food — the comparison becomes invalid, not just less precise.
(b)
Surround the test tube of water with a heat shield, such as an open-ended metal can with a hole for air, and keep the flame as close to the tube as possible. This traps more of the heat produced near the water rather than letting it escape into the surrounding air, so a greater proportion of the energy released by the food is transferred to (and measured in) the water.
(c)
Repeating reduces the effect of random errors (such as slight differences in draughts or how evenly a sample burns) on any single trial. Averaging several trials gives a result closer to the true energy released by that food, and lets an unusually high or low (anomalous) result be identified and excluded.
QUESTION 11 3 marks Criterion C
Easy
BoxMass (kg)Height lifted (m)GPE gained (J)
A25100
B43?

The table shows two boxes lifted onto a shelf. Take $g = 10\,\text{N/kg}$. Calculate the GPE gained by Box B.

Show complete worked solution

$$ E_p = mgh = 4 \times 10 \times 3 $$

Answer: $E_p = 120\,\text{J}$

QUESTION 12 4 marks Criterion C
Medium
Toy carMass (kg)Speed (m/s)Kinetic energy (J)
10.521
20.544
30.569
40.5864
50.51025

All five toy cars have the same mass. The kinetic energy for each was calculated using $E_k = \tfrac{1}{2}mv^2$.

a. Identify the anomalous kinetic energy value in the table.
[1]
b. Calculate the correct kinetic energy for Car 4, showing your working.
[2]
c. Suggest one likely explanation for how this anomalous value arose.
[1]
Show complete worked solution
(a)
Car 4's value of $64\,\text{J}$ is anomalous.
(b)
$$ E_k = \tfrac{1}{2} \times 0.5 \times 8^2 = \tfrac{1}{2} \times 0.5 \times 64 = 16\,\text{J} $$
(c)
It was most likely a calculation or recording error (for example, the speed value may have been mistyped or misread, or the wrong number substituted into the formula).
QUESTION 13 5 marks Criterion C
Medium
0 15 30 45 60 16 Wood 30 Coal 46 Petrol 55 Natural gas Fuel Energy released (MJ per kg)

The bar chart shows the approximate energy released when $1\,\text{kg}$ of each fuel is completely burned.

a. Which fuel releases the most energy per kilogram, and how much?
[1]
b. Calculate how many times more energy natural gas releases per kilogram than wood does.
[2]
c. A small boat can carry $200\,\text{kg}$ of fuel. Calculate the total energy available if it is loaded with coal.
[2]
Show complete worked solution
(a)
Natural gas releases the most energy per kilogram, at $55\,\text{MJ/kg}$.
(b)
$$ \frac{55}{16} = 3.4 \text{ (2 s.f.)} $$

Answer: natural gas releases about 3.4 times as much energy per kilogram as wood.

(c)
$$ 200\,\text{kg} \times 30\,\text{MJ/kg} = 6000\,\text{MJ} $$
QUESTION 14 5 marks Criterion C
Medium
Speed (m/s)0102030
Kinetic energy (kJ)050200450

The table shows the kinetic energy of a $1000\,\text{kg}$ car at different speeds.

a. Describe the pattern between speed and kinetic energy shown in the table.
[2]
b. Use this pattern (without recalculating from the formula) to predict the kinetic energy at $40\,\text{m/s}$.
[2]
c. Explain why doubling a car's speed is more dangerous in a collision than doubling its mass would be.
[1]
Show complete worked solution
(a)
As the speed doubles (for example from $10$ to $20\,\text{m/s}$), the kinetic energy does not simply double — it quadruples ($50\,\text{kJ} \to 200\,\text{kJ}$). Kinetic energy increases with the square of speed, not in direct proportion to it.
(b)
$40\,\text{m/s}$ is double $20\,\text{m/s}$, so the kinetic energy should be $4$ times greater: $$ 200\,\text{kJ} \times 4 = 800\,\text{kJ} $$
(c)
Kinetic energy depends on $v^2$ but only on $m^1$, so doubling the speed quadruples the kinetic energy while doubling the mass only doubles it — a faster car releases far more energy in a collision than a heavier car travelling at the same speed.
QUESTION 15 4 marks Criterion C
Medium
HikerMass (kg)Height climbed (m)GPE gained (J)
Amir6010060 000
Beth40100?
Chen6015090 000

Three hikers climb the same hill via different routes, reaching different heights. Take $g = 10\,\text{N/kg}$.

a. Calculate the GPE gained by Beth.
[2]
b. A student claims: “The hiker who reaches the greatest height always gains the most energy.” Using the data, evaluate whether this claim is fully correct.
[2]
Show complete worked solution
(a)
$$ E_p = mgh = 40 \times 10 \times 100 = 40\,000\,\text{J} $$
(b)
Chen did reach the greatest height ($150\,\text{m}$) and did gain the most GPE ($90\,000\,\text{J}$) in this table — but that is because GPE depends on both mass and height ($E_p = mgh$). The claim is not always true: a lighter hiker climbing higher will not necessarily gain more energy than a much heavier hiker climbing a smaller height, since a large enough mass can outweigh a smaller height difference.
QUESTION 16 7 marks Criterion C
Hard
Mass of wax burned (g)12345
Energy released (kJ)408012095200

A student burns different masses of the same candle wax and measures the energy released using a data logger.

a. Identify the anomalous result, and use the pattern in the rest of the data to estimate roughly what value would have been expected instead.
[2]
b. Suggest a possible experimental reason for this anomalously low reading.
[2]
c. Using only the four consistent readings, calculate the mean energy released per gram of wax.
[3]
Show complete worked solution
(a)
The reading for $4\,\text{g}$ ($95\,\text{kJ}$) is anomalous. The other readings follow a clear pattern of about $40\,\text{kJ}$ released per gram, so a value of roughly $4 \times 40 = 160\,\text{kJ}$ would have been expected.
(b)
The $4\,\text{g}$ sample may not have burned completely (for example if it was blown out or ran short of oxygen partway through), so less of its stored chemical energy was actually released and transferred to be measured.
(c)
$$ \frac{40}{1} = 40, \quad \frac{80}{2} = 40, \quad \frac{120}{3} = 40, \quad \frac{200}{5} = 40 \;\text{(all in kJ/g)} $$

Answer: mean energy released $= 40\,\text{kJ per gram}$ of wax.

QUESTION 17 8 marks Criterion C
Hard
Student1234
Temperature rise (°C)18421920

Four students each measured the temperature rise of $100\,\text{g}$ of water after a $5\,\text{g}$ peanut sample was burned beneath it. Use the formula: $$\text{energy transferred to water (J)} = \text{mass of water (g)} \times 4.2 \times \text{temperature rise (}^\circ\text{C)}$$

a. Identify the anomalous result.
[1]
b. Calculate the mean temperature rise using only the three consistent readings.
[2]
c. Using the given formula and your mean temperature rise, calculate the energy transferred to the water.
[3]
d. The peanut sample had a mass of $5\,\text{g}$. Use your answer to (c) to calculate the energy released per gram of peanut in this experiment.
[2]
Show complete worked solution
(a)
Student 2's reading of $42\,^\circ\text{C}$ is anomalous.
(b)
$$ \frac{18 + 19 + 20}{3} = \frac{57}{3} = 19\,^\circ\text{C} $$
(c)
$$ \text{energy} = 100 \times 4.2 \times 19 = 7980\,\text{J} \approx 7.98\,\text{kJ} $$
(d)
$$ \frac{7980}{5} = 1596\,\text{J/g} \approx 1.6\,\text{kJ/g} $$

(This is much lower than a peanut's true energy content because a lot of heat escapes into the surrounding air rather than reaching the water.)

QUESTION 18 5 marks Criterion D
Medium

Energy drinks contain large amounts of sugar, which provides the body with a large amount of chemical energy that can be used quickly.

Discuss one benefit and one drawback of regularly consuming high-energy drinks, using ideas about energy.

Show complete worked solution

Benefit: The large amount of chemical energy in sugar can be quickly converted for use by the body, giving a fast source of energy for short bursts of intense activity — useful, for example, for athletes needing rapid fuel during exercise.

Drawback: If the chemical energy taken in is greater than the energy the body actually uses, the excess is stored as fat, which over time can contribute to health problems such as obesity. The high sugar content can also damage teeth, and regular high-energy drinks often contain caffeine, which can affect sleep and cause dependency.

QUESTION 19 5 marks Criterion D
Medium

Nuclear power stations release very large amounts of energy from a small mass of uranium fuel, without burning any fuel or producing greenhouse gases during operation.

Discuss one benefit and one drawback of using nuclear fuel as an energy source.

Show complete worked solution

Benefit: A very small mass of uranium releases an enormous amount of energy compared with the same mass of a fossil fuel, and nuclear power stations do not release carbon dioxide or other greenhouse gases while generating electricity, making them useful for providing large, reliable amounts of energy without directly worsening climate change.

Drawback: Nuclear power produces radioactive waste that remains hazardous for many thousands of years and must be stored extremely carefully, at high cost, to avoid harming people and the environment. There is also a small but serious risk of accidents releasing dangerous radiation over a wide area.

QUESTION 20 6 marks Criterion D
Hard

Some countries have very few natural energy sources of their own — no fossil fuel reserves, and limited sunshine or wind for renewable generation — so they must import fuel from other countries to generate electricity.

Evaluate the benefit and the drawback of a country relying heavily on imported energy sources.

Show complete worked solution

Benefit: Importing fuel allows a country without its own energy resources to still access a reliable energy supply, supporting homes, industry, and economic activity that would otherwise be impossible without local coal, oil, gas, or strong renewable conditions.

Drawback: Depending on other countries for energy makes the supply vulnerable to events outside the importing country's control — for example price rises, political conflicts, or disruption to shipping and pipelines in the exporting country — all of which threaten energy security. Transporting fuel over long distances also adds cost and, if the fuel is a fossil fuel, additional emissions from transport.

Energy Transfers and Transformations 20 questions

QUESTION 1 3 marks Criterion A
Easy

Electrical appliances transform electrical energy into other, more useful forms.

a. State the energy transformation that occurs in an electric kettle.
[1]
b. State the energy transformation that occurs in a loudspeaker.
[1]
c. State the energy transformation that occurs in a solar panel.
[1]
Show complete worked solution
(a)
Electrical energy ? thermal (heat) energy — the heating element converts electrical energy into heat, transferred to the water.
(b)
Electrical energy ? sound energy (with some wasted heat energy in the coil/magnet).
(c)
Light energy ? electrical energy.
QUESTION 2 2 marks Criterion A
Easy

An electric motor is supplied with $100\,\text{J}$ of electrical energy. It usefully transforms $70\,\text{J}$ of this into kinetic energy; the rest is wasted as heat and sound. Calculate the efficiency of the motor as a percentage.

Show complete worked solution

Step 1 — State the formula:

$$ \text{efficiency} = \frac{\text{useful energy output}}{\text{total energy input}} \times 100\% $$

Step 2 — Substitute:

$$ \text{efficiency} = \frac{70}{100} \times 100\% $$

Answer: efficiency $= 70\%$

QUESTION 3 2 marks Criterion A
Easy

A lamp is supplied with $60\,\text{J}$ of electrical energy and produces $9\,\text{J}$ of useful light energy. Calculate the energy wasted, and state the form this wasted energy mostly takes.

Show complete worked solution

Wasted energy $= 60 - 9 = 51\,\text{J}$.

This wasted energy is mostly transferred as heat (thermal energy) to the surroundings.

QUESTION 4 4 marks Criterion A
Medium

A washing machine motor is supplied with $500\,\text{J}$ of electrical energy each cycle. It usefully transfers $350\,\text{J}$ of this to kinetic energy of the drum.

a. Calculate the efficiency of the motor.
[2]
b. Calculate the wasted energy.
[1]
c. State two forms this wasted energy might take.
[1]
Show complete worked solution
(a)
$$ \text{efficiency} = \frac{350}{500} \times 100\% = 70\% $$
(b)
$$ 500 - 350 = 150\,\text{J} $$
(c)
Heat (thermal) energy and sound energy, produced mainly by friction in the motor and drum mechanism.
QUESTION 5 4 marks Criterion A
Medium
Elastic potential energy (in spring) Kinetic energy (of car) Thermal energy + sound Wind-up toy car released and rolling to a stop

A wind-up toy car has its internal spring wound up, then is released so it drives across the floor, gradually slowing down and stopping due to friction.

a. Name the form of energy stored while the spring is wound up.
[1]
b. Name the main form of energy the car has while it is moving across the floor.
[1]
c. Explain what happens to the car's kinetic energy once it eventually stops.
[2]
Show complete worked solution
(a)
Elastic potential energy.
(b)
Kinetic energy.
(c)
Friction between the wheels/floor and inside the mechanism transforms the kinetic energy into thermal energy (and a small amount of sound), which spreads out into the surroundings. The total amount of energy is unchanged — it has just been transferred into forms that are no longer useful for driving the car.
QUESTION 6 4 marks Criterion A
Medium

A solar panel has an efficiency of $18\%$. It receives $2000\,\text{J}$ of light energy from the Sun.

a. State the efficiency formula.
[1]
b. Calculate the useful electrical energy output of the panel.
[3]
Show complete worked solution
(a)
$$ \text{efficiency} = \frac{\text{useful energy output}}{\text{total energy input}} \times 100\% $$
(b)
$$ \text{useful output} = \text{efficiency} \times \text{input} = 0.18 \times 2000 $$

Answer: $360\,\text{J}$

QUESTION 7 6 marks Criterion A
Hard

An LED bulb transforms electrical energy into light with an efficiency of $80\%$. It produces $40\,\text{J}$ of useful light energy every second.

a. Rearrange the efficiency formula to make total input energy the subject.
[2]
b. Calculate the total electrical energy supplied to the bulb per second.
[2]
c. Calculate the wasted energy per second, and state where this energy is mainly transferred to.
[2]
Show complete worked solution
(a)
$$ \text{efficiency} = \frac{\text{useful output}}{\text{input}} \times 100\% \;\Rightarrow\; \text{input} = \frac{\text{useful output}}{\text{efficiency}} \times 100\% $$
(b)
$$ \text{input} = \frac{40}{80} \times 100 = 50\,\text{J} $$
(c)
$$ 50 - 40 = 10\,\text{J} $$

This $10\,\text{J}$ per second is mainly transferred as heat to the surroundings.

QUESTION 8 6 marks Criterion B
Medium

A student wants to compare how much energy is wasted as heat by an LED bulb and a filament bulb of the same power rating, by measuring the temperature rise of the air just above each bulb after it has been switched on for a fixed time.

a. State the independent and dependent variables in this investigation.
[2]
b. State one variable that should be controlled, and explain why.
[2]
c. Suggest one way to make sure the thermometer reading is a fair measure of the heat given off by each bulb.
[2]
Show complete worked solution
(a)
Independent variable: type of bulb (LED or filament). Dependent variable: temperature rise of the air above the bulb.
(b)
Control the time each bulb is switched on for (and their power rating). If one bulb were left on for longer, it would show a bigger temperature rise regardless of how wasteful it actually is, making the comparison unfair.
(c)
Position the thermometer at exactly the same distance above each bulb every time, and make sure the starting (room) temperature is the same for both tests — for example, by waiting for each bulb and its surroundings to cool back to room temperature before testing the next one.
QUESTION 9 6 marks Criterion B
Medium

A student wants to investigate whether the efficiency of a small electric motor changes as it lifts different masses. The motor lifts each mass through a fixed height using a string over a pulley, while a joulemeter measures the electrical energy supplied.

a. State the independent and dependent variables.
[2]
b. State two variables that should be controlled, and explain why for one of them.
[2]
c. Describe how the student would calculate the efficiency for each mass tested.
[2]
Show complete worked solution
(a)
Independent variable: mass being lifted. Dependent variable: efficiency of the motor (calculated from the GPE gained by the mass and the electrical energy supplied).
(b)
Control the height each mass is lifted through and the voltage/power supplied to the motor. Why control the height: lifting a mass through a greater height would give it more useful GPE regardless of the motor's efficiency, making it impossible to fairly compare results between different masses.
(c)
Use the joulemeter reading for the electrical energy supplied, and calculate the useful GPE gained by the mass using $E_p = mgh$ (with the known mass and fixed height). Efficiency is then calculated as $$ \text{efficiency} = \frac{\text{GPE gained}}{\text{electrical energy supplied}} \times 100\% $$ for each mass tested.
QUESTION 10 8 marks Criterion B
Hard

In the motor-lifting investigation above, the calculated efficiency turned out to be much lower than the motor's stated (manufacturer's) efficiency.

a. Suggest one reason, other than the motor's own inefficiency, why the calculated efficiency might come out artificially low.
[3]
b. Suggest an improvement to the apparatus that would reduce this source of error.
[3]
c. Explain why repeating the experiment and calculating a mean efficiency would improve reliability, even though it would not fix this source of error.
[2]
Show complete worked solution
(a)
Friction in the pulley (and air resistance on the string and mass) also wastes some of the mechanical energy the motor actually outputs, before it reaches the mass as useful GPE. This means not all the energy the motor genuinely converts to kinetic/mechanical energy ends up recorded as GPE gained — making the measured efficiency lower than the motor's true efficiency.
(b)
Use a low-friction pulley (for example, one with ball bearings) and a light, smooth string running vertically and directly in line with the pulley, minimising extra energy losses that are not caused by the motor itself.
(c)
Repeating and averaging reduces the effect of random variations between trials (such as small timing differences when switching the joulemeter, or the mass swinging slightly as it lifts), giving a value closer to the motor's typical efficiency under these conditions. However, since the pulley friction affects every trial in the same way, averaging would not remove this systematic underestimate.
QUESTION 11 3 marks Criterion C
Easy
ApplianceEnergy input (J)Useful energy output (J)
Kettle1000900

Calculate the efficiency of the kettle.

Show complete worked solution

$$ \text{efficiency} = \frac{900}{1000} \times 100\% $$

Answer: efficiency $= 90\%$

QUESTION 12 5 marks Criterion C
Medium
Bulb typeEnergy input (J)Useful light output (J)
Filament1005
LED10080

The table compares two bulbs supplied with the same electrical energy.

a. Calculate the efficiency of each bulb.
[2]
b. Calculate the wasted energy for the filament bulb.
[1]
c. State the main form this wasted energy takes.
[1]
d. Suggest why LED bulbs, despite often costing more to buy, might be cheaper to run over time.
[1]
Show complete worked solution
(a)
Filament: $$ \frac{5}{100} \times 100\% = 5\% $$ LED: $$ \frac{80}{100} \times 100\% = 80\% $$
(b)
$$ 100 - 5 = 95\,\text{J} $$
(c)
Heat (thermal energy).
(d)
Because LEDs waste far less energy as heat (only $20\%$ wasted, compared with $95\%$ for a filament bulb), much less electrical energy — and therefore money — is needed to produce the same amount of useful light.
QUESTION 13 5 marks Criterion C
Medium
0 15 30 45 60 35% Coal 50% Gas (CCGT) 33% Nuclear 45% Wind turbine Power station type Efficiency (%)

The bar chart shows the approximate efficiency of different types of power station at converting their energy source into useful electrical energy.

a. Which type of power station has the highest efficiency shown, and what is it?
[1]
b. A gas power station is supplied with $800\,\text{MJ}$ of chemical energy. Calculate the wasted energy.
[2]
c. A coal power station is supplied with the same $800\,\text{MJ}$. Calculate how much more useful energy the gas station produces than the coal station for this same input.
[2]
Show complete worked solution
(a)
Gas (CCGT) power stations, at $50\%$ efficiency.
(b)
Useful output $= 0.50 \times 800 = 400\,\text{MJ}$, so wasted energy $= 800 - 400 = 400\,\text{MJ}$.
(c)
Coal useful output $= 0.35 \times 800 = 280\,\text{MJ}$. Gas useful output $= 400\,\text{MJ}$ (from (b)). Difference $= 400 - 280 = 120\,\text{MJ}$ more from the gas station.
QUESTION 14 5 marks Criterion C
Medium

An incandescent (filament) lamp is supplied with $100\,\text{W}$ of electrical power. It produces $5\,\text{W}$ of useful light and $95\,\text{W}$ of heat.

A student claims: “Since $95\,\text{W}$ is 'wasted', this lamp must be broken and unsafe to use.”

a. Calculate the efficiency of the lamp.
[2]
b. Evaluate the student's claim that the lamp must be “broken” because so much energy is wasted.
[2]
c. Suggest one reason the wasted heat is not completely “useless” in every situation.
[1]
Show complete worked solution
(a)
$$ \frac{5}{100} \times 100\% = 5\% $$
(b)
The claim is incorrect — this is normal behaviour for a filament lamp, not a fault. Filament lamps produce light by heating a thin wire filament until it glows white-hot, so the vast majority of the electrical energy inevitably ends up as heat rather than light. A very low efficiency like $5\%$ does not mean the lamp is faulty or unsafe; it simply means this type of lamp is very inefficient compared with, for example, an LED bulb.
(c)
In a cold room in winter, the heat given off might usefully warm the room slightly — though relying on lamps to heat a room is a very inefficient way of doing so compared with a proper heater, so this is only an incidental benefit, not a reason to design lamps this way.
QUESTION 15 4 marks Criterion C
Medium
Hour1234
Energy input from water (MJ)1000100010001000
Electrical energy output (MJ)900910400895

A hydroelectric power station's energy input and output were recorded over four hours.

a. Calculate the efficiency of the power station during hour 1.
[1]
b. Identify the anomalous hour, and suggest a possible reason for this reading.
[2]
c. Should hour 3's reading be included when calculating the station's typical efficiency? Justify your answer.
[1]
Show complete worked solution
(a)
$$ \frac{900}{1000} \times 100\% = 90\% $$
(b)
Hour 3 is anomalous ($400\,\text{MJ}$ output, far below the pattern of about $900\,\text{MJ}$). A likely reason is a temporary mechanical fault, reduced water flow, or scheduled maintenance that reduced the station's output during that hour.
(c)
No — it should be excluded, since it does not represent the station's normal operating efficiency and would make the calculated typical efficiency misleadingly low; the cause of the drop should be investigated separately.
QUESTION 16 7 marks Criterion C
Hard
VehicleEnergy input per km (MJ)Useful kinetic energy output per km (MJ)
Petrol car3.60.9
Electric car1.20.9

The table compares a petrol car and an electric car travelling the same $1\,\text{km}$ distance, producing the same amount of useful kinetic energy.

a. Calculate the efficiency of each car.
[3]
b. A journalist claims: “Electric cars need three times less input energy for the same useful output, so they must be three times more efficient.” Evaluate this claim using your answers to (a).
[2]
c. Explain why comparing these two efficiency figures alone does not tell the full story about which vehicle is better for the environment.
[2]
Show complete worked solution
(a)
Petrol car: $$ \frac{0.9}{3.6} \times 100\% = 25\% $$ Electric car: $$ \frac{0.9}{1.2} \times 100\% = 75\% $$
(b)
The claim happens to be correct in this case: the input energy is indeed $3$ times less ($1.2\,\text{MJ}$ vs $3.6\,\text{MJ}$) and the efficiency is also $3$ times greater ($75\%$ vs $25\%$). However, this only follows directly because the useful output is exactly equal for both cars — efficiency compares output to input as a ratio, so “times less input” only translates neatly into “times more efficient” when the useful outputs being compared are the same.
(c)
These efficiencies only measure how well each vehicle converts the energy supplied to it into useful motion — they do not account for how that supplied energy was originally produced (electricity may itself come from burning fossil fuels at a power station, which has its own losses and emissions) or the energy used in extracting, refining and transporting petrol. A full environmental comparison needs to consider the whole energy supply chain, not just each vehicle's own efficiency figure.
QUESTION 17 8 marks Criterion C
Hard
Trial12345
Electrical energy input (J)5050505050
GPE gained by mass (J)211982220

A student repeated the motor-lifting experiment five times, each time supplying $50\,\text{J}$ of electrical energy.

a. Calculate the efficiency for each trial, and identify which trial's result looks anomalous.
[3]
b. Calculate the mean efficiency using only the four consistent trials.
[2]
c. Suggest a reason trial 3 might have given such a low result.
[2]
d. Explain why using the mean of several trials gives a more reliable estimate of the motor's efficiency than using a single trial.
[1]
Show complete worked solution
(a)
Trial 1: $\frac{21}{50}\times100=42\%$. Trial 2: $\frac{19}{50}\times100=38\%$. Trial 3: $\frac{8}{50}\times100=16\%$. Trial 4: $\frac{22}{50}\times100=44\%$. Trial 5: $\frac{20}{50}\times100=40\%$. Trial 3 (16%) is anomalous.
(b)
$$ \frac{42 + 38 + 44 + 40}{4} = \frac{164}{4} = 41\% $$
(c)
The string may have slipped on the pulley or motor spindle during that trial, so much of the electrical energy did not effectively lift the mass — or the mass may not have been securely attached and did not rise the full measured height.
(d)
A single trial could be affected unpredictably by a one-off problem (like slipping), whereas averaging several consistent trials reduces the impact of such random errors, and lets a wildly different (anomalous) trial be identified and excluded — giving a result closer to the motor's true typical efficiency.
QUESTION 18 5 marks Criterion D
Medium

Many countries require new appliances, such as fridges and washing machines, to display an energy efficiency label (for example, a rating from A to G) showing how efficiently they use electricity.

Discuss one benefit and one drawback of these labelling schemes.

Show complete worked solution

Benefit: Efficiency labels help consumers make informed choices by clearly showing which appliances waste less energy, encouraging people to buy more efficient models. This reduces household electricity bills over the appliance's lifetime and lowers the amount of energy wasted nationally, which can reduce the fossil fuels burned (and emissions produced) at power stations.

Drawback: More efficient appliances are often more expensive to buy, which can be a barrier for lower-income households, even though they would save money on bills over time. Rating scales can also change or be updated over the years, which can confuse consumers comparing an older label to a newer one.

QUESTION 19 5 marks Criterion D
Medium

Replacing old filament light bulbs with LED bulbs across a whole country could hugely reduce national electricity use, since LEDs waste far less energy as heat than filament bulbs do.

Discuss one benefit and one drawback of a national scheme to replace all filament bulbs with LEDs.

Show complete worked solution

Benefit: Since LEDs waste far less energy as heat, a nationwide switch would significantly reduce the total electricity demand for lighting. This lowers household running costs and reduces the amount of fuel burned (and greenhouse gases released) at power stations that generate that electricity.

Drawback: The upfront cost of replacing bulbs and fittings across an entire country could be expensive, particularly for households and businesses that cannot easily afford it. Throwing away large numbers of still-working filament bulbs also creates waste, and manufacturing millions of new LED bulbs has its own environmental impact (energy use, materials, and eventual disposal).

QUESTION 20 6 marks Criterion D
Hard

No machine can ever be $100\%$ efficient — some energy is always transformed into non-useful forms, such as heat and sound, which spread out into the surroundings.

Evaluate the importance of continuing to research and develop more efficient technologies (such as engines, motors, and power stations), discussing both a benefit and a limitation of this effort.

Show complete worked solution

Benefit: Even a small efficiency improvement, applied to technology used on a massive scale (such as car engines or power stations), can save an enormous total amount of energy across a country or the world. This reduces the fossil fuels burned, lowers greenhouse gas emissions, and reduces running costs for individuals and businesses over time.

Limitation: Because no device can ever reach $100\%$ efficiency, technologies that are already quite efficient can only be improved by smaller and smaller amounts — often at increasing cost, complexity, and research time, a pattern known as diminishing returns. Resources spent chasing very small further efficiency gains might sometimes achieve more if instead directed at reducing overall energy demand or switching to renewable energy sources altogether.

Conservation of Energy 20 questions

QUESTION 1 3 marks Criterion A
Easy

The law of conservation of energy is one of the most important ideas in science.

a. State the law of conservation of energy.
[1]
b. A ball is dropped and falls freely towards the ground (ignore air resistance). Name the energy transformation taking place as it falls.
[1]
c. State what would happen to the ball's "missing" energy if some energy were instead lost to air resistance as it fell.
[1]
Show complete worked solution
(a)
Energy cannot be created or destroyed — it can only be transferred from one place to another, or transformed from one form into another. The total amount of energy in a closed system stays constant.
(b)
Gravitational potential energy ? kinetic energy.
(c)
It would not truly be lost or destroyed — it would be transferred to thermal (heat) energy and sound in the surrounding air, due to friction (drag) between the ball and the air.
QUESTION 2 2 marks Criterion A
Easy

A ball of mass $2\,\text{kg}$ is released from rest at the top of a frictionless hill $5\,\text{m}$ high. Take $g = 10\,\text{N/kg}$. Using the law of conservation of energy, calculate the kinetic energy of the ball when it reaches the bottom of the hill.

Show complete worked solution

Since the hill is frictionless, all of the ball's GPE at the top transforms into KE by the time it reaches the bottom (no energy is transformed into other, non-useful forms).

$$ E_p(\text{top}) = mgh = 2 \times 10 \times 5 = 100\,\text{J} $$

Answer: $E_k(\text{bottom}) = 100\,\text{J}$

QUESTION 3 2 marks Criterion A
Easy

A trolley of mass $4\,\text{kg}$ has $72\,\text{J}$ of kinetic energy. Calculate its speed.

Show complete worked solution

Step 1 — Rearrange the kinetic energy formula:

$$ E_k = \tfrac{1}{2}mv^2 \;\Rightarrow\; v = \sqrt{\frac{2E_k}{m}} $$

Step 2 — Substitute:

$$ v = \sqrt{\frac{2 \times 72}{4}} = \sqrt{36} $$

Answer: $v = 6\,\text{m/s}$

QUESTION 4 4 marks Criterion A
Medium

A stone of mass $0.5\,\text{kg}$ is dropped from a height of $20\,\text{m}$ and falls freely, with air resistance small enough to ignore. Take $g = 10\,\text{N/kg}$.

a. Calculate the GPE of the stone at the moment it is released.
[1]
b. Using the law of conservation of energy, state the value of the stone's kinetic energy just before it hits the ground.
[1]
c. Calculate the stone's speed just before it hits the ground.
[2]
Show complete worked solution
(a)
$$ E_p = mgh = 0.5 \times 10 \times 20 = 100\,\text{J} $$
(b)
$100\,\text{J}$ — with no air resistance, all of the GPE transforms into KE by the time the stone reaches the ground.
(c)
$$ v = \sqrt{\frac{2E_k}{m}} = \sqrt{\frac{2 \times 100}{0.5}} = \sqrt{400} $$

Answer: $v = 20\,\text{m/s}$

QUESTION 5 4 marks Criterion A
Medium
h highest point (max GPE) highest point (max GPE) lowest point (max KE)

A pendulum bob of mass $0.2\,\text{kg}$ is pulled to one side and released from rest. At its highest point it has $4\,\text{J}$ of gravitational potential energy relative to its lowest point. Assume there is no friction at the pivot and no air resistance.

a. State the value of the bob's kinetic energy at the lowest point of its swing, using the law of conservation of energy.
[1]
b. Calculate the speed of the bob at the lowest point of its swing, to 3 significant figures.
[3]
Show complete worked solution
(a)
$4\,\text{J}$ — all of the GPE at the highest point transforms into KE by the time the bob reaches the lowest point, since no energy is transformed into other forms.
(b)
$$ v = \sqrt{\frac{2E_k}{m}} = \sqrt{\frac{2 \times 4}{0.2}} = \sqrt{40} $$

Answer: $v = 6.32\,\text{m/s}$ (3 s.f.)

QUESTION 6 4 marks Criterion A
Medium

A skateboarder has $800\,\text{J}$ of GPE at the top of a ramp. At the bottom of the ramp, she has $650\,\text{J}$ of kinetic energy.

a. Calculate the energy "lost" to friction as she goes down the ramp.
[1]
b. Explain, using the law of conservation of energy, why describing this energy as "lost" is not strictly accurate.
[2]
c. State what the total of KE + heat + sound produced would equal, if all forms could be measured.
[1]
Show complete worked solution
(a)
$$ 800 - 650 = 150\,\text{J} $$
(b)
The total amount of energy is always conserved — it cannot be destroyed. This $150\,\text{J}$ has not disappeared; it has been transformed into other, less useful forms, mainly heat energy (from friction between the wheels and the ramp) and a small amount of sound, which spread out into the surroundings.
(c)
It would equal the original $800\,\text{J}$ of GPE — the total energy is always conserved, even though it has spread into several different, less useful forms.
QUESTION 7 6 marks Criterion A
Hard

A $2\,\text{kg}$ ball is released from rest at a height of $8\,\text{m}$ on a frictionless track. It rolls down, then up a second frictionless hill. Take $g = 10\,\text{N/kg}$.

a. Using the law of conservation of energy, explain why, if the second hill is tall enough, the ball will reach exactly $8\,\text{m}$ on the second hill before momentarily coming to rest.
[2]
b. In reality, the ball only reaches a height of $6.5\,\text{m}$ on the second hill. Calculate how much energy was transformed into non-useful forms between the start and this point.
[3]
c. State the name of the law being applied throughout this question.
[1]
Show complete worked solution
(a)
With no friction, all of the ball's initial GPE converts fully into KE by the bottom of the first hill, and then all of that KE converts back fully into GPE as it rises up the second hill (no energy is transformed into non-useful forms anywhere in the system). Since GPE $=mgh$ depends only on mass and height for a given ball, the ball must regain exactly its original height of $8\,\text{m}$ before its KE (and therefore its speed) returns to zero again.
(b)
$$ E_p(\text{start}) = mgh = 2 \times 10 \times 8 = 160\,\text{J} $$$$ E_p(6.5\,\text{m}) = 2 \times 10 \times 6.5 = 130\,\text{J} $$

Energy transformed to non-useful forms $= 160 - 130 = 30\,\text{J}$ (mainly to heat and sound, due to friction and air resistance).

(c)
The law of conservation of energy.
QUESTION 8 6 marks Criterion B
Medium

A student wants to investigate how the height a ball is dropped from affects the height it rebounds to, in order to explore how energy is transformed during the bounce.

a. State the independent and dependent variables.
[2]
b. State two variables that should be controlled, and explain why for one of them.
[2]
c. Describe how the student could use the drop height and rebound height data to calculate what percentage of the ball's GPE is converted back into GPE after each bounce.
[2]
Show complete worked solution
(a)
Independent variable: drop height. Dependent variable: rebound (bounce) height.
(b)
Control the ball used (same ball every time) and the surface it bounces on. Why control the ball: a different ball may compress and deform differently on impact, losing a different proportion of its energy regardless of drop height, which would make comparing results between drop heights unfair.
(c)
For each drop, calculate the GPE just before dropping ($E_p = mgh_{\text{drop}}$) and the GPE at the top of the rebound ($E_p = mgh_{\text{rebound}}$); since mass and $g$ are the same throughout, this simplifies to comparing the heights directly: $$ \text{percentage "conserved"} = \frac{h_{\text{rebound}}}{h_{\text{drop}}} \times 100\% $$ This shows what proportion of the ball's energy remains as GPE after the bounce, with the rest transformed to heat and sound during the impact.
QUESTION 9 6 marks Criterion B
Medium

A student wants to investigate how the surface material of a ramp (for example, smooth plastic compared with rough carpet) affects how much of a trolley's starting GPE is converted into KE by the bottom of the ramp. A light gate connected to a timer is used to measure the trolley's speed as it crosses the bottom of the ramp.

a. State the independent and dependent variables.
[2]
b. State one variable that should be controlled, and explain why.
[2]
c. Explain how the light gate measurement is used to calculate the trolley's KE at the bottom of the ramp.
[2]
Show complete worked solution
(a)
Independent variable: surface material of the ramp. Dependent variable: kinetic energy of the trolley at the bottom of the ramp (or the percentage of GPE converted to KE).
(b)
Control the release height of the trolley (and the trolley used, so its mass stays the same). If the release height changed between tests, the trolley would start with a different amount of GPE regardless of the surface, making the comparison between surfaces unfair.
(c)
The light gate and timer measure how long the trolley takes to pass through the beam, over a known small width on the trolley; dividing this width by the time gives the trolley's speed, $v = \dfrac{\text{width}}{\text{time}}$. This speed is then substituted into $E_k = \tfrac{1}{2}mv^2$, along with the trolley's known mass, to calculate its kinetic energy at the bottom for each surface tested.
QUESTION 10 8 marks Criterion B
Hard

In the ball-drop investigation above, measuring the exact rebound height by eye is difficult, because the ball reaches its highest point only briefly before falling again.

a. Explain why measuring rebound height by eye could lead to unreliable results.
[2]
b. Suggest an improvement to the method that would make the rebound height measurement more reliable, and explain how it works.
[3]
c. Explain why repeating each drop height multiple times and taking a mean rebound height would further improve the investigation.
[3]
Show complete worked solution
(a)
Human reaction time and judgement mean the observer may misjudge the exact highest point reached, especially since the ball moves quickly and pauses only momentarily at that height. Small differences between trials caused simply by mis-judging the height could look like real differences in energy loss, when they are actually just measurement error.
(b)
Use a video camera (for example, slow-motion recording on a smartphone) to film the bounce next to a fixed metre ruler, then play back the footage frame by frame to identify the exact highest point reached and read off the height accurately. This removes the need to judge the position of a fast-moving ball by eye in real time.
(c)
No two bounces are perfectly identical — tiny differences in exactly how the ball lands, spins, or the small imperfections in the surface can each affect the result slightly. A single trial might not represent the ball's typical behaviour at that drop height, so averaging several trials reduces the effect of this natural variability (and any remaining measurement error), giving a more reliable representation of the true relationship between drop height and rebound height.
QUESTION 11 3 marks Criterion C
Easy
PositionHeight (m)GPE (J)KE (J)
Top102000
Middle5100?
Bottom00200

The table shows the GPE and KE of a $2\,\text{kg}$ ball at three points as it falls freely (ignore air resistance). Using the law of conservation of energy (total mechanical energy $=$ GPE $+$ KE $=$ constant, since there is no air resistance), calculate the missing KE value at the middle point.

Show complete worked solution

At the top, all the energy is GPE, so the total mechanical energy is $200 + 0 = 200\,\text{J}$. This total stays constant throughout the fall.

At the middle point: $$ \text{KE} = 200 - 100 = 100\,\text{J} $$

QUESTION 12 5 marks Criterion C
Medium
PointHeight (m)GPE (J)KE (J)
A (start)2020000
B (bottom)001800
C (top of 2nd hill)151500200

A $10\,\text{kg}$ cart on a roller-coaster track is measured at three points, A, B and C.

a. Calculate the total mechanical energy (GPE + KE) at each of the three points.
[2]
b. Explain what has happened to the "missing" energy between point A and point B.
[2]
c. State whether more energy was transformed to non-useful forms between A and B, or between B and C. Justify your answer using your answers to (a).
[1]
Show complete worked solution
(a)
A: $2000 + 0 = 2000\,\text{J}$. B: $0 + 1800 = 1800\,\text{J}$. C: $1500 + 200 = 1700\,\text{J}$.
(b)
$2000 - 1800 = 200\,\text{J}$ is missing from the mechanical energy total between A and B. This energy has not disappeared: by the law of conservation of energy, it must have been transformed into other forms — mainly heat energy, and some sound, produced by friction between the cart's wheels and the track (and air resistance) as it moved from A to B.
(c)
More was transformed between A and B ($2000 - 1800 = 200\,\text{J}$ lost) than between B and C ($1800 - 1700 = 100\,\text{J}$ lost), based on the mechanical energy totals calculated in (a).
QUESTION 13 4 marks Criterion C
Medium
Drop height (cm)1005025
Rebound height (cm)643216

The table shows the drop and rebound heights of a bouncy ball, all measured on the same surface.

a. Calculate the percentage of the ball's GPE "retained" (returned as rebound height) for the drop from $100\,\text{cm}$.
[2]
b. Show that the same percentage applies to the other two drops in the table.
[1]
c. Predict the rebound height for a drop height of $200\,\text{cm}$, using this pattern.
[1]
Show complete worked solution
(a)
$$ \frac{64}{100} \times 100\% = 64\% $$
(b)
$50\,\text{cm}$ drop: $\dfrac{32}{50}\times100\%=64\%$. $25\,\text{cm}$ drop: $\dfrac{16}{25}\times100\%=64\%$. Both match the $64\%$ found in (a).
(c)
$$ 200 \times 0.64 = 128\,\text{cm} $$
QUESTION 14 5 marks Criterion C
Medium
PositionHeight above lowest point (m)GPE (J)KE (J)
Start (released)0.210
Lowest point001

A pendulum bob of mass $0.5\,\text{kg}$ is released from rest, as shown in the table. Take $g = 10\,\text{N/kg}$. Assume no friction or air resistance.

a. Calculate the speed of the bob at the lowest point.
[3]
b. A student suggests that using a heavier bob, released from the same height, would make it swing faster at the lowest point. Evaluate this claim using ideas about conservation of energy.
[2]
Show complete worked solution
(a)
$$ v = \sqrt{\frac{2E_k}{m}} = \sqrt{\frac{2 \times 1}{0.5}} = \sqrt{4} $$

Answer: $v = 2\,\text{m/s}$

(b)
The claim is incorrect. Using $E_p = mgh = E_k = \tfrac{1}{2}mv^2$, the mass $m$ appears on both sides and cancels out, giving $v^2 = 2gh$ — the speed at the lowest point depends only on $g$ and the release height $h$, not on the mass of the bob. A heavier bob would gain proportionally more GPE at the same height, but would also need proportionally more KE to reach any given speed; these two effects cancel exactly, so (ignoring air resistance) a heavier bob reaches the same speed at the lowest point, not a faster one.
QUESTION 15 4 marks Criterion C
Medium
RampHeight (m)Length of ramp (m)Speed at bottom (m/s)
Steep5610
Shallow51210

Two frictionless ramps, one steep and one shallow, both start at the same height. A ball of the same mass is released from rest at the top of each.

a. Compare the speeds of the ball at the bottom of the two ramps.
[1]
b. Explain why the speeds are the same, using the law of conservation of energy.
[3]
Show complete worked solution
(a)
The speeds are the same, $10\,\text{m/s}$, even though the shallow ramp is twice as long as the steep ramp.
(b)
Both ramps start at the same height ($5\,\text{m}$) with the same mass of ball, so both balls have exactly the same initial GPE ($E_p = mgh$). Since neither ramp has friction, all of this GPE converts into KE by the bottom of each ramp — so both balls end up with the same KE, and therefore the same speed, regardless of the ramp's length or shape. GPE and KE (and so the final speed, from $v = \sqrt{2gh}$) depend only on the height dropped, not on the path taken to get there.
QUESTION 16 7 marks Criterion C
Hard
PointHeight (m)GPE (J)KE (J)
A (start)1020000
B48001050
C (end, flat ground)001600

A $20\,\text{kg}$ skateboarder is measured at three points, A, B and C, in a skate park.

a. Calculate the total mechanical energy at points B and C.
[2]
b. Calculate the total energy transformed to non-useful forms (such as heat and sound) between A and C.
[2]
c. Calculate this $400\,\text{J}$ as a percentage of the skater's initial energy at A.
[2]
d. The skater notices they cannot quite reach the original height of $10\,\text{m}$ on a return ramp. Explain why, using your answer to (c).
[1]
Show complete worked solution
(a)
B: $800 + 1050 = 1850\,\text{J}$. C: $0 + 1600 = 1600\,\text{J}$.
(b)
Total mechanical energy at A $= 2000 + 0 = 2000\,\text{J}$. Energy transformed $= 2000 - 1600 = 400\,\text{J}$.
(c)
$$ \frac{400}{2000} \times 100\% = 20\% $$
(d)
Because $20\%$ of the skater's original mechanical energy has already been transformed into non-useful forms (heat and sound, from friction and air resistance) by the time they reach C, there is not enough mechanical energy remaining to regain the full original height of $10\,\text{m}$ — the skater can only rise as high as the energy they still have allows.
QUESTION 17 8 marks Criterion C
Hard
Trial1234
Release height (cm)80808080
Height reached on far ramp (cm)68527069

A student releases a trolley from rest on a curved track and measures the height it reaches on a second ramp on the far side, repeating the test four times from the same $80\,\text{cm}$ release height.

a. Calculate the percentage of energy "conserved" (returned as height) for trials 1, 3 and 4.
[2]
b. Identify the anomalous trial, giving a reason for excluding it from the mean.
[2]
c. Calculate the mean percentage of energy conserved using the three consistent trials, to 3 significant figures.
[2]
d. Using your mean value, explain why the trolley's height on the far ramp will always be a little less than its release height, even in a carefully designed experiment.
[2]
Show complete worked solution
(a)
Trial 1: $\dfrac{68}{80}\times100\%=85\%$. Trial 3: $\dfrac{70}{80}\times100\%=87.5\%$. Trial 4: $\dfrac{69}{80}\times100\%=86.25\%$.
(b)
Trial 2 ($52\,\text{cm}$, $65\%$) is far lower than the other three, consistent results ($85$–$87.5\%$), suggesting an error occurred — for example, the trolley may have derailed slightly, or been released with a small knock rather than truly from rest — so it should be excluded as unrepresentative.
(c)
$$ \frac{85 + 87.5 + 86.25}{3} = \frac{258.75}{3} = 86.25\% \approx 86.3\% \text{ (3 s.f.)} $$
(d)
It is essentially impossible to eliminate friction (for example, between the trolley's wheels/axle and the track) and air resistance completely. Some mechanical energy is always transformed into heat and sound, so the height regained (and therefore the GPE regained) will always be slightly less than the original — a truly frictionless system exists only in idealised theory, not in a real experiment.
QUESTION 18 5 marks Criterion D
Medium

In a normal car, the brakes convert the car's kinetic energy into heat through friction, which spreads into the surroundings and cannot be reused. Many electric and hybrid cars instead use "regenerative braking", where the motor runs in reverse to convert kinetic energy back into electrical energy, stored in the battery for later use.

Discuss one benefit and one drawback of regenerative braking systems.

Show complete worked solution

Benefit: Regenerative braking significantly improves the overall efficiency of a vehicle by reusing energy that would otherwise be transformed into wasted heat, instead storing it as useful electrical energy in the battery. This extends the vehicle's driving range and reduces the total energy (and fuel or electricity) it needs.

Drawback: Regenerative braking systems add extra cost, weight, and complexity to a vehicle, since the motor must be able to work in reverse as a generator as well as drive the wheels. They also typically cannot recover all of the car's kinetic energy — some is still transformed into heat and sound — and under heavy or emergency braking, conventional friction brakes are usually still needed alongside the regenerative system for full stopping power.

QUESTION 19 5 marks Criterion D
Medium

Occasionally, inventors claim to have built a "perpetual motion machine" — a device that, once started, keeps producing energy forever without any energy input, or that produces more useful energy than is put into it.

Discuss one way the law of conservation of energy helps protect people from such claims, and one drawback that arises when this scientific reasoning is ignored.

Show complete worked solution

How the law helps: Because energy cannot be created, only transformed, the law of conservation of energy immediately tells scientists and engineers that a machine which produces more energy output than input, indefinitely, is impossible — some energy is always transformed into other forms (such as heat and sound, through friction and air resistance) in any real machine. This lets people quickly and confidently identify a claimed "free energy" device as impossible, without needing to test it in detail.

Drawback when ignored: Despite this, people offering "perpetual motion" or "free energy" devices have, throughout history, defrauded investors and members of the public out of large amounts of money, because sound scientific reasoning based on the conservation of energy is sometimes ignored in favour of exciting but impossible promises — a clear example of how understanding a fundamental scientific law helps protect people from being misled.

QUESTION 20 6 marks Criterion D
Hard

Pumped-storage hydroelectric power stations pump water uphill into a reservoir using electrical energy when electricity demand (and price) is low, then release the water back downhill through turbines to generate electricity again when demand is high.

Evaluate the benefit and the limitation of this technology, using ideas about conservation of energy.

Show complete worked solution

Benefit: This allows excess electrical energy — for example, from wind turbines generating more electricity than is needed overnight — to be stored, by transforming it into gravitational potential energy of the pumped water, rather than being wasted. This stored energy can then be converted back into electricity within minutes when it is needed most, helping match a variable electricity supply (especially from renewable sources) to variable demand.

Limitation: By the law of conservation of energy, no energy transformation is ever $100\%$ efficient — pumping the water uphill wastes some energy as heat and sound in the pumps and pipes, and generating electricity again as the water flows back down wastes further energy in the turbines and generators. Overall, a pumped-storage system typically returns noticeably less electrical energy than was originally used to pump the water uphill (a round-trip efficiency of roughly $70$–$80\%$), so it should be understood as an efficient way to store energy for later use, not a way to create extra energy.

Work and Power (basic) 20 questions

QUESTION 1 2 marks Criterion A
Easy

A worker pushes a crate with a steady force of $20\,\text{N}$, moving it $5\,\text{m}$ in the direction of the force. Calculate the work done on the crate.

Show complete worked solution

Step 1 — State the formula:

$$ W = F \times d $$

Step 2 — Substitute:

$$ W = 20 \times 5 $$

Answer: $W = 100\,\text{J}$

QUESTION 2 2 marks Criterion A
Easy

An electric motor transfers $500\,\text{J}$ of energy in $10\,\text{s}$. Calculate its power output.

Show complete worked solution

Step 1 — State the formula:

$$ P = \frac{W}{t} $$

Step 2 — Substitute:

$$ P = \frac{500}{10} $$

Answer: $P = 50\,\text{W}$

QUESTION 3 3 marks Criterion A
Easy

In physics, work is only done on an object when a force causes it to move some distance in the direction of that force.

a. A person pushes hard against a heavy wall, but the wall does not move at all. Has any work been done on the wall? Explain.
[1]
b. A person carries a heavy bag while walking at a constant height across a flat floor. Explain whether they are doing work against gravity.
[1]
c. A crane lifts a box straight upward. Explain why work IS being done in this case.
[1]
Show complete worked solution
(a)
No work is done. Although a force is applied, the wall does not move ($d = 0$), so $W = F \times d = 0$.
(b)
No work is done against gravity, because the bag's height above the ground is not changing — there is no vertical distance moved in the direction of the upward force needed to support the bag's weight.
(c)
A force is applied (upward, to overcome the box's weight) and the box moves a distance in the direction of that force (upward), so work is done: $W = F \times d$.
QUESTION 4 4 marks Criterion A
Medium

A forklift truck exerts an upward force of $4000\,\text{N}$ to lift a pallet, doing $12\,000\,\text{J}$ of work in the process.

a. State the formula for work done.
[1]
b. Rearrange the formula to make distance $d$ the subject.
[1]
c. Calculate the height the pallet is lifted.
[2]
Show complete worked solution
(a)
$$ W = F \times d $$
(b)
$$ d = \frac{W}{F} $$
(c)
$$ d = \frac{12\,000}{4000} $$

Answer: $d = 3\,\text{m}$

QUESTION 5 4 marks Criterion A
Medium

An electric winch does $6000\,\text{J}$ of work lifting a load in $15\,\text{s}$.

a. Calculate the power of the winch.
[2]
b. The winch is later upgraded so that it can lift the same load, doing the same amount of work, in only $10\,\text{s}$. Calculate its new power.
[2]
Show complete worked solution
(a)
$$ P = \frac{W}{t} = \frac{6000}{15} = 400\,\text{W} $$
(b)
$$ P = \frac{W}{t} = \frac{6000}{10} = 600\,\text{W} $$
QUESTION 6 4 marks Criterion A
Medium

A weightlifter lifts an $80\,\text{kg}$ barbell a height of $2\,\text{m}$. Take $g = 10\,\text{N/kg}$.

a. Calculate the force needed to lift the barbell (equal to its weight).
[1]
b. Calculate the work done lifting the barbell.
[2]
c. State how this work done relates to the gravitational potential energy (GPE) gained by the barbell.
[1]
Show complete worked solution
(a)
$$ F = mg = 80 \times 10 = 800\,\text{N} $$
(b)
$$ W = F \times d = 800 \times 2 = 1600\,\text{J} $$
(c)
They are equal — the work done against gravity while lifting the barbell is transferred to it as GPE, so the barbell gains $1600\,\text{J}$ of GPE.
QUESTION 7 6 marks Criterion A
Hard

A pump does $90\,000\,\text{J}$ of work raising water in $2.5$ minutes.

a. Convert the time to seconds.
[1]
b. Calculate the power of the pump, in watts.
[2]
c. Express this power in kilowatts (kW).
[1]
d. The pump is found to require an electrical power input of $750\,\text{W}$ to achieve this. Calculate its efficiency.
[2]
Show complete worked solution
(a)
$$ 2.5 \times 60 = 150\,\text{s} $$
(b)
$$ P = \frac{W}{t} = \frac{90\,000}{150} = 600\,\text{W} $$
(c)
$600\,\text{W} \div 1000 = \textbf{0.6 kW}$
(d)
$$ \text{efficiency} = \frac{600}{750} \times 100\% $$

Answer: $80\%$

QUESTION 8 6 marks Criterion B
Medium

A student wants to measure her own power output by timing how long it takes her to climb a flight of stairs of known height, then calculating the work done against gravity and her power output.

a. State what measurements and equipment the student needs to take before she can calculate her power.
[2]
b. State how the work done climbing the stairs would be calculated.
[2]
c. State how her power output would then be calculated from this work done.
[2]
Show complete worked solution
(a)
Her own mass (using bathroom scales), the height of the stairs (using a tape measure, or the height of one step multiplied by the number of steps), and the time taken to climb the stairs (using a stopwatch).
(b)
Work done $=$ weight $\times$ height climbed $= (mass \times g) \times$ height, since climbing the stairs raises her body weight against gravity through that vertical height.
(c)
$$ \text{power} = \frac{\text{work done}}{\text{time taken to climb the stairs}} $$
QUESTION 9 6 marks Criterion B
Medium

A student wants to investigate how carrying an additional load (a rucksack) affects the power she needs to develop to climb the same flight of stairs at her fastest safe pace.

a. State the independent and dependent variables.
[2]
b. State one variable that should be controlled, and explain why.
[2]
c. Describe how the student would calculate her power for each load tested.
[2]
Show complete worked solution
(a)
Independent variable: mass of the load carried (rucksack mass). Dependent variable: power developed (calculated from work done and time taken).
(b)
Control the height of the stairs climbed each time. If the height climbed changed between tests, that alone would change the work done and power required, regardless of the load carried, making the comparison unfair.
(c)
Weigh herself plus the rucksack each time to find the total mass being lifted; measure the time taken to climb the fixed-height stairs; calculate work done using $W = (\text{total mass} \times g) \times \text{height}$, then power $= \dfrac{W}{t}$.
QUESTION 10 8 marks Criterion B
Hard

In the stair-climbing power investigation, the student repeated the climb five times at each load, and noticed her power readings became gradually lower with each repeat.

a. Suggest why her power readings might decrease over repeated trials.
[2]
b. Explain why this fatigue effect is a problem for getting a fair, repeatable measurement of her "typical" power output.
[2]
c. Suggest one change to the method that would reduce this problem.
[2]
d. Suggest one additional source of timing error in this experiment, and how it could be reduced.
[2]
Show complete worked solution
(a)
She is likely becoming tired (fatigued) from repeatedly climbing the stairs, so she cannot climb as quickly in later trials — this increases the time taken while the work done (mass $\times g \times$ height) stays the same, reducing her calculated power.
(b)
The decreasing trend is caused by tiredness building up between trials, not by random measurement error, so the trials are not truly independent repeats of the same conditions. Simply averaging all five trials would give a misleadingly low estimate of her actual maximum, typical power output.
(c)
Allow a longer rest period between each climb (for example, several minutes, until her breathing and heart rate return to normal), so she is fully recovered before each attempt, rather than climbing repeatedly with little or no rest.
(d)
Hand-timing with a stopwatch introduces reaction-time error at the start and end of each climb. This could be reduced by using automatic timing (for example, light gates or sensors) that start and stop as she passes fixed points, removing human reaction time from the measurement.
QUESTION 11 3 marks Criterion C
Easy
BoxForce (N)Distance moved (m)Work done (J)
A504200
B306?

Calculate the work done moving Box B.

Show complete worked solution

$$ W = F \times d = 30 \times 6 $$

Answer: $W = 180\,\text{J}$

QUESTION 12 5 marks Criterion C
Medium
AppliancePower (W)Time used (hours)
Toaster10000.1
Hairdryer15000.2
Phone charger53

The table shows three appliances and how long each was used for on a particular day.

a. Calculate the energy used by the toaster, in J. (Hint: convert the time to seconds first: $0.1$ hours $= 360\,\text{s}$.)
[1]
b. Calculate the energy used by the hairdryer, in J. ($0.2$ hours $= 720\,\text{s}$.)
[1]
c. A student claims: “The phone charger, because it's plugged in for so much longer, must use more energy overall today than the toaster's single use.” Evaluate this claim using a calculation. ($3$ hours $= 10\,800\,\text{s}$.)
[3]
Show complete worked solution
(a)
$$ E = P \times t = 1000 \times 360 = 360\,000\,\text{J} = 360\,\text{kJ} $$
(b)
$$ E = 1500 \times 720 = 1\,080\,000\,\text{J} = 1080\,\text{kJ} $$
(c)
$$ E_{\text{charger}} = 5 \times 10\,800 = 54\,000\,\text{J} = 54\,\text{kJ} $$

The claim is incorrect: even over $3$ hours, the phone charger only uses $54\,\text{kJ}$, far less than the $360\,\text{kJ}$ used by the toaster in a single $6$-minute use. This is because total energy used depends on both the power rating and the time used — the toaster's much higher power ($1000\,\text{W}$ vs $5\,\text{W}$) far outweighs its much shorter usage time.

QUESTION 13 5 marks Criterion C
Medium
0 300 600 900 1200 100 Walking 400 Jogging 1000 Cycling sprint 1200 100m sprint Activity Power output (W)

The bar chart shows the approximate average power output of a person doing different activities.

a. Which activity requires the greatest power output, and how much?
[1]
b. A student does $3000\,\text{J}$ of work while walking. Using the power value from the chart, calculate how long this walk lasted.
[2]
c. Calculate how much work would be done while sprinting for the same $30\,\text{s}$, and compare it to your answer to (b).
[2]
Show complete worked solution
(a)
A $100\,\text{m}$ sprint, at $1200\,\text{W}$.
(b)
$$ t = \frac{W}{P} = \frac{3000}{100} = 30\,\text{s} $$
(c)
$$ W = P \times t = 1200 \times 30 = 36\,000\,\text{J} $$

This is $\dfrac{36\,000}{3000} = 12$ times more work than walking for the same $30\,\text{s}$, matching the fact that the sprint's power output ($1200\,\text{W}$) is exactly $12$ times greater than walking's ($100\,\text{W}$).

QUESTION 14 4 marks Criterion C
Medium
Load carried (kg)0510
Total work done (J)240030003600
Time taken (s)121415

A student climbs the same flight of stairs carrying different loads, and the work done and time taken are recorded.

a. Calculate the power developed for the $0\,\text{kg}$ and $10\,\text{kg}$ loads.
[2]
b. Describe the trend shown as the load carried increases.
[1]
c. Suggest why her power might not keep increasing indefinitely as the load carried increases further.
[1]
Show complete worked solution
(a)
$0\,\text{kg}$: $\dfrac{2400}{12}=200\,\text{W}$. $10\,\text{kg}$: $\dfrac{3600}{15}=240\,\text{W}$.
(b)
Both the work done and the power developed increase as the load carried increases — carrying more weight requires more work to lift up the same height, and here the time taken increases by proportionally less than the work does, so her power output rises too.
(c)
Eventually the extra weight would become too tiring to carry at a fast pace, forcing her to slow down significantly — this much longer time, despite the greater work done, would cause her power to level off or even decrease again.
QUESTION 15 4 marks Criterion C
Medium
CrateForce needed (N)Height lifted (m)Work done (J)
12003600
220051000
320041200
420061200

A crane lifts four crates using the same $200\,\text{N}$ force, to different heights. The work done for each was calculated using $W = F \times d$.

a. Identify the anomalous work-done value in the table.
[1]
b. Calculate the correct work done for crate 3, showing your working.
[2]
c. Suggest one likely explanation for how this anomalous value arose.
[1]
Show complete worked solution
(a)
Crate 3's value of $1200\,\text{J}$ is anomalous — it matches crate 4's value, despite crate 3 being lifted to a smaller height.
(b)
$$ W = F \times d = 200 \times 4 = 800\,\text{J} $$
(c)
It was most likely a recording or calculation error — for example, the height for crate 3 may have been mistyped as $6\,\text{m}$ (crate 4's height) instead of $4\,\text{m}$ when the work done was calculated.
QUESTION 16 7 marks Criterion C
Hard
TrialMechanical work done cranking (J)Time (s)Electrical energy produced (J)
1120020900
21500251125
3100020300

A hand-crank generator's mechanical work input and electrical energy output were measured over three trials.

a. Calculate the power input (mechanical) for trial 1.
[2]
b. Calculate the efficiency of energy transfer for each trial, and identify which trial is anomalous.
[3]
c. Suggest a possible reason for trial 3's anomalous result.
[2]
Show complete worked solution
(a)
$$ P = \frac{W}{t} = \frac{1200}{20} = 60\,\text{W} $$
(b)
Trial 1: $\dfrac{900}{1200}\times100\%=75\%$. Trial 2: $\dfrac{1125}{1500}\times100\%=75\%$. Trial 3: $\dfrac{300}{1000}\times100\%=30\%$. Trial 3 is anomalous — its efficiency ($30\%$) is far lower than the consistent $75\%$ shown by trials 1 and 2.
(c)
A loose wire connection may have meant some of the generator's electrical output wasn't properly transferred to the measuring meter, or the crank mechanism may have slipped internally, reducing how effectively the mechanical cranking that trial was converted into measured electricity.
QUESTION 17 8 marks Criterion C
Hard
StudentMass (kg)Height of stairs (m)Time taken (s)
A50612
B65615
C80612

Three students each climb the same flight of stairs, and their mass and time taken are recorded. Take $g = 10\,\text{N/kg}$.

a. Calculate the work done by each student in climbing the stairs.
[3]
b. Calculate the power developed by each student.
[3]
c. A teacher claims: “Student C is definitely the fittest, because they have the highest power output.” Evaluate this claim.
[2]
Show complete worked solution
(a)
A: $W=mgh=50\times10\times6=3000\,\text{J}$. B: $65\times10\times6=3900\,\text{J}$. C: $80\times10\times6=4800\,\text{J}$.
(b)
A: $\dfrac{3000}{12}=250\,\text{W}$. B: $\dfrac{3900}{15}=260\,\text{W}$. C: $\dfrac{4800}{12}=400\,\text{W}$.
(c)
Student C does have the highest raw power output ($400\,\text{W}$), but this is partly because they have a much greater mass ($80\,\text{kg}$) than students A and B, so they must do more work simply to lift their own greater body weight up the same height. A fairer comparison might use power per kilogram of body mass: A $=\frac{250}{50}=5\,\text{W/kg}$, B $=\frac{260}{65}=4\,\text{W/kg}$, C $=\frac{400}{80}=5\,\text{W/kg}$. By this measure, A and C are actually equal, and B is lowest — a rather different picture than comparing raw power alone suggests.
QUESTION 18 5 marks Criterion D
Medium

Fast electric vehicle chargers can deliver very high power (for example, $150\,\text{kW}$) to recharge a car's battery in a fraction of the time taken by a standard home charger (about $7\,\text{kW}$).

Discuss one benefit and one drawback of installing many high-power fast chargers.

Show complete worked solution

Benefit: Much shorter charging times make electric vehicles far more convenient for long journeys, removing one of the main barriers to owning one. This can encourage more people to switch away from petrol and diesel cars, potentially reducing local air pollution and emissions from transport.

Drawback: Delivering very high power to many vehicles at once places a large demand on the local electricity grid, which may require expensive upgrades to cables and substations to cope. If that electricity is generated from fossil fuels, fast charging does not necessarily reduce overall emissions as much as expected, and the high currents involved can also cause faster degradation of a car's battery over time.

QUESTION 19 5 marks Criterion D
Medium

In some areas without reliable access to mains electricity, hand-crank or pedal-powered generators are used to charge radios, lights, and phones, or to pump water, using a person's own muscular effort to develop power.

Discuss one benefit and one drawback of these human-powered devices.

Show complete worked solution

Benefit: These devices let people without access to mains electricity or fuel still generate small amounts of usable power for essential needs — such as lighting, charging a phone, or pumping water — using only their own effort, with no fuel costs or dependence on grid infrastructure. This is especially useful in remote areas or during power cuts.

Drawback: The human body can only sustainably develop a fairly small amount of power for extended periods (a fit adult can typically sustain roughly $75$–$100\,\text{W}$), so these devices can only provide small amounts of energy compared with mains electricity, and require ongoing physical effort and cause fatigue in the user — limiting how much they can practically be relied upon.

QUESTION 20 6 marks Criterion D
Hard

Machines such as engines and motors can sustain far higher continuous power output than any human, which is a major reason machines have replaced manual human labour in many industries, such as agriculture and construction.

Evaluate the benefit and the drawback of this widespread mechanisation, using ideas about power.

Show complete worked solution

Benefit: Because machines can sustain far higher power output than a human for far longer without tiring, tasks such as ploughing fields, lifting heavy loads, or manufacturing goods can be completed vastly faster and more efficiently than by manual labour. This has massively increased productivity and removed much of the physically exhausting, and sometimes dangerous, work that used to be required of people.

Drawback: Widespread mechanisation has eliminated many jobs that used to be done by people, causing unemployment and economic hardship in communities that relied on that manual work. In addition, the machines themselves usually require a continuous supply of fuel or electricity to sustain their high power output, and producing that energy can have its own significant environmental and economic costs.

Renewable vs Non-Renewable Resources 20 questions

QUESTION 1 4 marks Criterion A
Easy

Energy resources can be classified as renewable or non-renewable.

a. State whether solar energy is renewable or non-renewable, and explain why in one sentence.
[1]
b. State whether coal is renewable or non-renewable, and explain why.
[1]
c. State whether wind energy is renewable or non-renewable.
[1]
d. State whether natural gas is renewable or non-renewable.
[1]
Show complete worked solution
(a)
Renewable — sunlight is continuously available and will not run out on a human timescale.
(b)
Non-renewable — coal took millions of years to form from decayed plant matter, and is being used up far faster than it can be naturally replaced.
(c)
Renewable — wind is continuously generated by weather patterns driven by the Sun, and will not run out.
(d)
Non-renewable — like coal and oil, it is a fossil fuel formed over millions of years from the remains of ancient organisms, and is a finite (limited) resource.
QUESTION 2 2 marks Criterion A
Easy

Define what it means for an energy resource to be described as "renewable".

Show complete worked solution

A renewable energy resource is one that is naturally replenished (restored) at a rate similar to, or faster than, the rate at which it is used — so it will not run out on a human timescale. Examples include solar, wind, and hydroelectric power.

QUESTION 3 2 marks Criterion A
Easy

A $3\,\text{kW}$ electric heater is switched on for $4$ hours. Calculate the energy it uses, in kWh.

Show complete worked solution

Step 1 — State the formula:

$$ E = P \times t $$

Step 2 — Substitute:

$$ E = 3\,\text{kW} \times 4\,\text{h} $$

Answer: $E = 12\,\text{kWh}$

QUESTION 4 4 marks Criterion A
Medium

A wind turbine has a power output of $2\,\text{MW}$ when operating at full capacity. It operates at full capacity for $6$ hours on a particularly windy day.

a. Calculate the energy generated during these $6$ hours, in MWh.
[2]
b. State this answer in kWh.
[1]
c. Explain why a wind turbine's total energy output over a whole year is very difficult to predict exactly.
[1]
Show complete worked solution
(a)
$$ E = P \times t = 2 \times 6 = 12\,\text{MWh} $$
(b)
$12\,\text{MWh} \times 1000 = \textbf{12 000 kWh}$
(c)
Wind speed (and therefore the turbine's power output) constantly varies with the weather, which cannot be predicted with total accuracy far in advance — the turbine does not run at full power all the time, so its output changes unpredictably from hour to hour.
QUESTION 5 4 marks Criterion A
Medium

A solar farm has a maximum power output of $50\,\text{MW}$, but because of clouds and night-time, it only generates electricity at close to this maximum rate for an average of $5$ hours per day.

a. Calculate the energy generated by the solar farm in one day.
[2]
b. Calculate the energy generated in one year ($365$ days).
[2]
Show complete worked solution
(a)
$$ E = P \times t = 50 \times 5 = 250\,\text{MWh} $$
(b)
$$ E = 250 \times 365 = 91\,250\,\text{MWh} $$
QUESTION 6 4 marks Criterion A
Medium

A small hydroelectric generator on a stream has a constant power output of $15\,\text{kW}$.

a. State the formula relating energy, power, and time.
[1]
b. Calculate how long (in hours) the generator must run to produce $180\,\text{kWh}$ of energy.
[3]
Show complete worked solution
(a)
$$ E = P \times t $$
(b)
$$ t = \frac{E}{P} = \frac{180}{15} $$

Answer: $t = 12\,\text{hours}$

QUESTION 7 6 marks Criterion A
Hard

A wind farm consists of $40$ turbines, each with a power output of $2.5\,\text{MW}$ when running at full capacity. On average, due to varying wind speeds, the wind farm actually operates at only $35\%$ of this full-capacity output over the course of a year (its overall capacity factor). There are $8760$ hours in a year.

a. Calculate the total full-capacity power output of the whole wind farm, if all $40$ turbines ran at full power simultaneously.
[2]
b. Using the $35\%$ capacity factor, calculate the wind farm's average actual power output over the year.
[2]
c. Calculate the total energy the wind farm generates in a year, in MWh.
[2]
Show complete worked solution
(a)
$$ 40 \times 2.5 = 100\,\text{MW} $$
(b)
$$ 100 \times 0.35 = 35\,\text{MW} $$
(c)
$$ E = P \times t = 35 \times 8760 $$

Answer: $306\,600\,\text{MWh}$

QUESTION 8 6 marks Criterion B
Medium

A student builds a model wind turbine using a small electric motor as a generator, with blades attached to its shaft. She wants to investigate how the number of blades affects the voltage produced when a desk fan blows air onto it at a fixed speed.

a. State the independent and dependent variables.
[2]
b. State two variables that should be controlled, and explain why for one of them.
[2]
c. Describe one way the student could make sure her voltage readings are reliable.
[2]
Show complete worked solution
(a)
Independent variable: number of blades. Dependent variable: voltage produced (read from a voltmeter connected to the generator).
(b)
Control the fan speed/setting and the distance between the fan and the turbine. Why control fan speed: a faster fan speed would produce a higher voltage regardless of the number of blades, making it impossible to fairly compare results for different blade numbers.
(c)
Take several repeated voltage readings for each number of blades and calculate a mean, since the voltage may fluctuate slightly moment to moment due to turbulence in the airflow from the fan.
QUESTION 9 6 marks Criterion B
Medium

A student wants to investigate how the angle between a solar panel and a fixed lamp affects the voltage the panel produces, using a protractor to set each angle and a voltmeter to measure output.

a. State the independent and dependent variables.
[2]
b. State one variable that should be controlled, and explain why.
[2]
c. Describe how a protractor would be used in this investigation to help make the results reliable.
[2]
Show complete worked solution
(a)
Independent variable: angle between the panel and the light source. Dependent variable: voltage produced by the solar panel.
(b)
Control the distance between the lamp and the panel (and the lamp's brightness setting). Increasing the distance reduces the light intensity reaching the panel regardless of the angle, which would make the results impossible to compare fairly between angles.
(c)
The protractor is used to precisely measure and set the angle of the panel relative to the lamp (or a fixed baseline) for each trial, ensuring the intended angle is accurately and consistently reproduced each time, rather than being estimated by eye.
QUESTION 10 8 marks Criterion B
Hard

In the model wind turbine investigation above, the student noticed the voltmeter reading fluctuated noticeably (going up and down) even while testing a single number of blades at a constant fan setting.

a. Suggest a reason for this fluctuation, other than a change in the number of blades.
[2]
b. Suggest an improvement to the method that would give a more reliable single voltage reading for each number of blades.
[3]
c. Explain why this small-scale model, tested only with a desk fan, might give a misleading impression of how much energy a full-size wind turbine would generate in the real world.
[3]
Show complete worked solution
(a)
Airflow from a desk fan is turbulent rather than perfectly smooth and constant, so the actual speed and direction of air hitting the blades varies slightly moment to moment, even at a fixed fan setting — this causes the turbine's rotation speed, and therefore the voltage produced, to fluctuate.
(b)
Rather than taking one instantaneous reading, record the voltage continuously over a period of time (for example, using a data logger) and calculate a mean voltage over that time — or take several separate readings at different moments and average them — to smooth out the effect of the turbulent fluctuations.
(c)
A desk fan's short-term turbulence is on a much smaller scale than the variation in real wind speed over hours, days, and seasons that a full-size turbine experiences. A short, small-scale lab test cannot capture how a real turbine's output changes with genuinely variable — sometimes very low, sometimes very high — wind speeds across a whole year. The model is useful for exploring general trends, such as the effect of blade number, but cannot alone be used to accurately predict a real turbine's total annual energy output.
QUESTION 11 3 marks Criterion C
Easy
SourceCoalGasRenewablesNuclear
Percentage of electricity generated20%30%40%10%

A country generates a total of $300\,\text{TWh}$ of electricity in a year, split between sources as shown. Calculate how much electricity (in TWh) was generated from renewable sources.

Show complete worked solution

$$ 300 \times 0.40 $$

Answer: $120\,\text{TWh}$

QUESTION 12 5 marks Criterion C
Medium
0 15 30 45 15% 2015 20% 2017 28% 2019 35% 2021 42% 2023 Year Electricity from renewables (%)

The bar chart shows the percentage of a country's electricity generated from renewable sources over several years.

a. Describe the trend shown in the chart.
[1]
b. Calculate the increase in percentage points between 2015 and 2023.
[1]
c. The country generated $250\,\text{TWh}$ of electricity in total in 2023. Calculate how much came from renewable sources.
[2]
d. Predict, giving a reason, whether the percentage in 2025 is likely to be higher or lower than $42\%$.
[1]
Show complete worked solution
(a)
The percentage of electricity from renewable sources has increased steadily in every period shown, nearly tripling from $15\%$ in 2015 to $42\%$ in 2023.
(b)
$$ 42 - 15 = 27 \text{ percentage points} $$
(c)
$$ 250 \times 0.42 = 105\,\text{TWh} $$
(d)
Likely higher, since the data shows a consistent increase in every period recorded, suggesting continued investment in renewable energy infrastructure — though this is only a prediction based on a pattern, not a certainty, since the actual rate of increase could slow down or speed up.
QUESTION 13 5 marks Criterion C
Medium
SourceCO? emissions (g per kWh)Electricity generated (kWh)
Coal9001000
Gas4001000
Wind101000

The table shows typical carbon dioxide emissions per unit of electricity generated by three sources.

a. Calculate the total CO? emissions from generating $1000\,\text{kWh}$ of electricity using coal.
[1]
b. Calculate the total CO? emissions from generating the same $1000\,\text{kWh}$ using wind.
[1]
c. Calculate how many times greater the CO? emissions from coal are compared with wind, for the same amount of electricity generated.
[2]
d. Explain why wind power does not produce exactly zero CO? emissions, even though the spinning turbine itself releases no CO? while generating electricity.
[1]
Show complete worked solution
(a)
$$ 900 \times 1000 = 900\,000\,\text{g} = 900\,\text{kg} $$
(b)
$$ 10 \times 1000 = 10\,000\,\text{g} = 10\,\text{kg} $$
(c)
$$ \frac{900}{10} = 90 \text{ times greater} $$
(d)
The small emissions figure given for wind reflects CO? released during other stages of the turbine's life cycle — such as manufacturing its materials (steel, concrete, etc.), transporting and installing it, and eventually decommissioning it — not from the electricity generation process itself, which produces no direct emissions.
QUESTION 14 4 marks Criterion C
Medium
Time8am10am12pm2pm4pm
Solar panel output (kW)0.52.03.51.02.5

The table shows the power output of a solar panel measured at different times on a partly cloudy day.

a. Describe the general pattern of solar power output shown, ignoring the value at 2pm.
[1]
b. Identify the anomalous reading, and suggest a reason for it.
[2]
c. State one reason, based on this data, why solar power alone cannot provide a reliable, constant electricity supply.
[1]
Show complete worked solution
(a)
Output rises during the morning to a peak around midday ($3.5\,\text{kW}$ at 12pm) as the Sun gets higher in the sky, then would be expected to fall gradually again through the afternoon as the Sun gets lower.
(b)
The 2pm reading ($1.0\,\text{kW}$) is anomalous — it breaks the otherwise smooth rise-and-fall pattern. A likely cause is a cloud temporarily blocking the Sun at that time, briefly reducing the light reaching the panel.
(c)
Its output naturally varies throughout the day (zero at night, changing through the day as the Sun's position changes) and can be further reduced suddenly and unpredictably by weather such as passing cloud cover, so it cannot reliably supply constant power on its own without some form of backup or storage.
QUESTION 15 4 marks Criterion C
Medium
InstallationNumber of turbinesHomes powered per turbineTotal homes powered
Wind farm A25800?
Wind farm B4080032 000

The table compares two wind farms, where each turbine on average powers the same number of homes.

a. Calculate the total number of homes powered by Wind farm A.
[2]
b. Calculate how many more homes Wind farm B powers than Wind farm A.
[2]
Show complete worked solution
(a)
$$ 25 \times 800 = 20\,000 \text{ homes} $$
(b)
$$ 32\,000 - 20\,000 = 12\,000 \text{ more homes} $$
QUESTION 16 7 marks Criterion C
Hard
YearFossil fuels (%)Renewables (%)Nuclear (%)
2000651817
2023553015

The table shows the approximate global share of electricity generation from different sources in 2000 and 2023. A news headline claims: “Renewables have already overtaken fossil fuels as the world's main source of electricity.”

a. Calculate the change, in percentage points, for fossil fuels and for renewables between 2000 and 2023.
[2]
b. Evaluate the claim in the headline, using the data in the table.
[3]
c. Suggest why global electricity generation from fossil fuels can still be increasing in absolute terms (total TWh), even though its percentage share is falling.
[2]
Show complete worked solution
(a)
Fossil fuels: $65 - 55 = 10$ percentage point decrease. Renewables: $30 - 18 = 12$ percentage point increase.
(b)
The claim is false based on this data: even in 2023, fossil fuels still provide the largest single share of global electricity generation ($55\%$), compared with renewables at $30\%$ — nearly double. While renewables have grown significantly and fossil fuels have declined, renewables have not yet overtaken fossil fuels as the world's main source.
(c)
Global electricity demand overall has grown substantially since 2000 (more people, more electrical devices, growing economies), so even a smaller percentage share of a much larger total amount of electricity generated can still represent a larger absolute amount than a bigger percentage share of the smaller total generated in 2000.
QUESTION 17 8 marks Criterion C
Hard
YearRated capacity (MW)Actual annual energy generated (GWh)
2019100300
2020100310
202110090
2022100295
2023100305

A wind farm's rated capacity and actual annual energy generated are shown for five years. A source's capacity factor is calculated as: $$ \text{capacity factor} = \frac{\text{actual annual energy generated}}{\text{maximum possible annual energy at full rated capacity}} \times 100\% $$ where the maximum possible annual energy $=$ rated capacity (MW) $\times\ 8760$ hours (converted to GWh by dividing by $1000$).

a. Calculate the capacity factor for 2019, to 3 significant figures.
[3]
b. Identify the anomalous year and suggest a reason for it.
[2]
c. Calculate the mean annual energy generated using the four consistent years (excluding 2021), and use it to calculate a more representative capacity factor.
[3]
Show complete worked solution
(a)
Maximum possible energy $= 100 \times 8760 = 876\,000\,\text{MWh} = 876\,\text{GWh}$.$$ \text{capacity factor} = \frac{300}{876} \times 100\% = 34.2\% \text{ (3 s.f.)} $$
(b)
2021 is anomalous — only $90\,\text{GWh}$ generated, far below the roughly $300\,\text{GWh}$ typical of the other years. A likely reason is storm damage, an extended maintenance shutdown, or a technical fault taking turbines offline for a significant part of that year.
(c)
$$ \text{mean} = \frac{300+310+295+305}{4} = \frac{1210}{4} = 302.5\,\text{GWh} $$$$ \text{capacity factor} = \frac{302.5}{876} \times 100\% = 34.5\% \text{ (3 s.f.)} $$
QUESTION 18 5 marks Criterion D
Medium

Solar panels and wind turbines produce no direct CO? emissions while generating electricity, but manufacturing them requires large amounts of energy and raw materials, including some rare metals, and they eventually need replacing or recycling.

Discuss one benefit and one drawback of a country switching rapidly to wind and solar power.

Show complete worked solution

Benefit: A rapid switch dramatically cuts the ongoing CO? emissions and air pollution produced while generating electricity, helping combat climate change and improving air quality and public health over time. It also relies on free, effectively endless energy sources (sunlight and wind), rather than a finite fuel that must be continually mined, extracted, and burned.

Drawback: Manufacturing solar panels and wind turbines requires large amounts of energy, raw materials, and mining — including some rare or limited metals — meaning there is a significant upfront environmental impact and cost before any "clean" electricity is even generated. Responsibly disposing of and recycling old panels and turbine blades at the end of their working life is also a growing challenge, since recycling infrastructure for these specific materials is still limited in many places.

QUESTION 19 5 marks Criterion D
Medium

Because wind and solar power output depends on the weather, a country relying heavily on them needs a way to supply electricity during periods of little wind or sun — for example, using large-scale battery storage that stores excess electricity generated on windy or sunny days for use later.

Discuss one benefit and one drawback of countries building large-scale battery storage to support renewable energy.

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Benefit: Large-scale storage lets a country continue to rely mainly on renewable, low-emission electricity even when generation temporarily drops, by storing excess energy from windy or sunny periods for use later — improving the overall reliability of a renewable-heavy electricity grid without needing to burn fossil fuels as backup.

Drawback: Mining the raw materials needed for large-scale batteries (such as lithium and cobalt) has its own significant environmental impact, and in some cases raises human-rights concerns in the regions where they are mined. Batteries are also very expensive to build at a national scale, and typically only store enough energy for hours to a few days — not necessarily enough to cover longer periods of low wind or sun that can sometimes last for weeks.

QUESTION 20 6 marks Criterion D
Hard

Some developing countries and remote communities without access to a national electricity grid have started installing small-scale solar and wind systems directly in their villages, rather than waiting for large fossil-fuel power stations and long-distance transmission cables to reach them.

Evaluate the benefit and the challenge of this approach for these communities.

Show complete worked solution

Benefit: Small-scale solar and wind systems can be installed locally, relatively quickly, and often more cheaply than building a large power station and hundreds of kilometres of transmission cables. This gives communities access to electricity — for lighting, refrigeration, communication, and healthcare equipment — far sooner than waiting for national grid expansion, and without the cost and supply difficulties of transporting fossil fuels to remote areas.

Challenge: Small-scale renewable systems still depend on the weather, and without a large national grid to share power with other regions, or large-scale storage, communities can face periods without reliable electricity during poor weather. The technology can also be expensive to install and maintain, with specialist parts and expertise sometimes not locally available — meaning ongoing funding and support are needed for the systems to remain reliable in the long term.